MGVCL Exam Paper (30-07-2021 Shift 3)
In a power network, 375 kV is recorded at a 400 kV bus. A 45 MVAR, 400 kV shunt reactor is connected to the bus. What is the reactive power absorbed by the shunt reactor?

59.55 MVAR
49.55 MVAR
39.55 MVAR
69.55 MVAR

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
In a single phase energy meter, the pressure / voltage coil is wound on

the edges of the limb on the laminated core
both the limbs of the laminated core with different turns
the centre limb of the laminated core / the middle limb of the shunt magnet
both the limbs of the laminated core with same turns

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
If the velocity of wind is doubled then the power output will

reduced to half
increase by 6 times
increase by 8 times
doubled

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
Which of the following statements are correct?
(i) Advanced metering infrastructure (AMI) is typically more automated and allows real- time, on-demand interrogations with metering endpoints.
(ii) An Automated Meter Reading (AMR) device only communicates from the customer to the energy supplier.
(iii) AMR meters only provide kWh information and possible peak kW demand for the month.

(i) and (ii) only
(i), (ii) and (iii)
(i) and (iii) only
(ii) and (iii) only

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
Continuous and rapid variations in the load current magnitude which causes voltage variations is known as

Flicker
Voltage distortion
Harmonics
Voltage sag

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
The current flowing in to a balanced delta connected load through line 'a' is 10 A when the conductor of line ’b’ is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of ’abc’.

Ia₀ = 0 A.Ia₁ = (-5 + j2.88) A.Ia₂ = (5 - j2.88) A.
Ia₀ = 10 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A.
Ia₀ = 0 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A.
Ia₀ = 10 A.Ia₁ = (-5 + j2.44) A.Ia₂ = (5 - j2.44) A.

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP
MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 3)