MGVCL Exam Paper (30-07-2021 Shift 3) The process of peeling of rocks into layers is called Delta Brachans Exfoliation Sublimation Delta Brachans Exfoliation Sublimation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Consider a solar PV plant with the following specific conditions:Analysis period: 1 yearMeasured average solar irradiation intensity in 1 year: 150 kWh/m²Generator area of the PV plant: 10 m² Efficiency factor of the PV modules: 15%Electrical energy actually exported by plant to grid: 135 kWhCalculate the performance ratio. 60% 50% 80% 75% 60% 50% 80% 75% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,A - total solar panel area in meter square.r - efficiency of solar panelh - solar installation per meter square area.Solar panel performance ratio = Actual energy (kWh)/(A*r*h)= (135/(0.15*10*150))= 0.60= 60 % (in percentage)
MGVCL Exam Paper (30-07-2021 Shift 3) The magnetizing inrush current in a transformer is rich in the harmonic component. second third seventh fifth second third seventh fifth ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2nd harmonics contains - 60 to 55 %3rd harmonics contains - 40 - 50%
MGVCL Exam Paper (30-07-2021 Shift 3) In which of the following situations, there is no need to provide directional overcurrent protection. single end fed, single feeder double end fed, single feeder single end fed, parallel feeder ring main single end fed, single feeder double end fed, single feeder single end fed, parallel feeder ring main ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Directional overcurrent relay protection is used for parallel feeder and ring main system.It is not used for the protection of radial system.
MGVCL Exam Paper (30-07-2021 Shift 3) A three phase four pole 50 Hz induction motor has a rotor resistance of 0.02 Ω/phase and stand-still reactance of 0.5 Ω/phase. Calculate the speed at which the maximum torque is developed. 1475 rpm 1525 rpm 1440 rpm 1500 rpm 1475 rpm 1525 rpm 1440 rpm 1500 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Condition for maximum torque,Sm = R2/X2= 0.04Ns = (120*f)/P= (120*50)/4= 1500 rpmS = (Ns - Nr)/NsNr = Ns(1 - Sm)= 1500*(1 - 0.04)= 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) A 200/400 V, 20 kVA, 2-winding transformer is connected as an auto-transformer to transform 600 V to 200 V. Calculate the kVA rating of the auto-transformer. 60 kVA 30 kVA 50 kVA 25 kVA 60 kVA 30 kVA 50 kVA 25 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here auto transformer change voltage from 600 V to 200 V.Voltage ratio (a) = 600/200 = 3kVA rating of the auto-transformer = (a/(a - 1))*(kVA rating of auto transformer)= (3/2)*20= 30 kVA
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