MGVCL Exam Paper (30-07-2021 Shift 3) Nairobi negotiations are related to which of the following Organisation? UNESCO World Trade Organisation World Economic Forum The United Nations Children's Fund UNESCO World Trade Organisation World Economic Forum The United Nations Children's Fund ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A single phase full converter bridge, connected to 230 V, 50 Hz source is feeding a load R =10 Ω in series with a large inductance that makes the load current ripple free. For a firing angle of 450, calculate the rectification efficiency. 63.66% 76.66% 50.55% 28.33% 63.66% 76.66% 50.55% 28.33% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rectification efficiency = DC output power/AC input power
MGVCL Exam Paper (30-07-2021 Shift 3) Fill in the blanks with suitable Preposition from the given alternatives.BCCI receives____1000 applications for Team India head coach position over for since against over for since against ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Which of the following medium is used between CPU and RAM to speed up the processing power of a CPU? Flash memory DRAM Virtual memory Cache memory Flash memory DRAM Virtual memory Cache memory ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A 200/400 V, 20 kVA, 2-winding transformer is connected as an auto-transformer to transform 600 V to 200 V. Calculate the kVA rating of the auto-transformer. 50 kVA 25 kVA 30 kVA 60 kVA 50 kVA 25 kVA 30 kVA 60 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here auto transformer change voltage from 600 V to 200 V.Voltage ratio (a) = 600/200 = 3kVA rating of the auto-transformer = (a/(a - 1))*(kVA rating of auto transformer)= (3/2)*20= 30 kVA
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.53 H and 15.83 pF 0.53 mH and 15.83 pF 0.73 H and 13.85 pF 0.73 mH and 13.85 pF 0.53 H and 15.83 pF 0.53 mH and 15.83 pF 0.73 H and 13.85 pF 0.73 mH and 13.85 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
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