MGVCL Exam Paper (30-07-2021 Shift 3) Nairobi negotiations are related to which of the following Organisation? UNESCO The United Nations Children's Fund World Economic Forum World Trade Organisation UNESCO The United Nations Children's Fund World Economic Forum World Trade Organisation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Find the word which is correctly spelt from the given options. Obecity Syndrome Seriuous Abolishid Obecity Syndrome Seriuous Abolishid ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 400 W and -50 W. Calculate the reactive power taken by the load 350√3 VAR 450/√3 VAR 450√3 VAR 350/√3 VAR 350√3 VAR 450/√3 VAR 450√3 VAR 350/√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken (Q) = √3*(W1 - W2)= √3*(450 + 50)= √3*450 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) કામકાજમાં ધ્યાન કન્દ્રિત કરજો'.આ આજ્ઞાર્થ વાક્યની સંભાવનાર્થ વાક્યરચના કઈ હોઈ શકે? હવે તો કામકાજમાં ધ્યાન કેન્દ્રિત કરશો ને? કામકાજમાં ધ્યાન કેન્દ્રિત નથી કરવું? કામકાજમાં ધ્યાન કેન્દ્રિત કરી લીધું છે. હવે તો તમે કામકાજમાં ધ્યાન કેન્દ્રિત કરો. હવે તો કામકાજમાં ધ્યાન કેન્દ્રિત કરશો ને? કામકાજમાં ધ્યાન કેન્દ્રિત નથી કરવું? કામકાજમાં ધ્યાન કેન્દ્રિત કરી લીધું છે. હવે તો તમે કામકાજમાં ધ્યાન કેન્દ્રિત કરો. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.4 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.8 Hz 1.2 Hz 0.8 Hz 1.6 Hz 1.8 Hz 1.2 Hz 0.8 Hz 1.6 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (1.1/0.6)*cosδ= (1.1/0.6)*0.5= 0.91M = (H*s)/(πf)= 4/(50π)fn = (0..91/(4/50π))= 8.9 rad/sec= 1.2 Hz
MGVCL Exam Paper (30-07-2021 Shift 3) When was the Constitution of India adopted by the Constituent Assembly? 26th November 1949 13th January 1950 January 25 1930 15th August 1947 26th November 1949 13th January 1950 January 25 1930 15th August 1947 ANSWER DOWNLOAD EXAMIANS APP
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