MGVCL Exam Paper (30-07-2021 Shift 3) In public sector, what is the full form of "LIC"? Life Insurance Company Life Insurance Corporation Life Insurers Lively Insurance Corporation Life Insurance Company Life Insurance Corporation Life Insurers Lively Insurance Corporation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Name the application under MS Office software bundle, that we use to create audio- visual presentation. MS Excel MS Access MS Word MS Power point MS Excel MS Access MS Word MS Power point ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The magnetizing inrush current in a transformer is rich in the harmonic component. seventh third fifth second seventh third fifth second ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2nd harmonics contains - 60 to 55 %3rd harmonics contains - 40 - 50%
MGVCL Exam Paper (30-07-2021 Shift 3) Arunachal Pradesh does not share its borders with which one of the following nations? China Bhutan Myanmar Bangladesh China Bhutan Myanmar Bangladesh ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Match the following shown in table A = (ii), B = (iii), C = (i) A = (ii), B = (i), C = (iii) A = (iii), B = (ii), C = (i) A = (iii), B = (i), C = (ii) A = (ii), B = (iii), C = (i) A = (ii), B = (i), C = (iii) A = (iii), B = (ii), C = (i) A = (iii), B = (i), C = (ii) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Bus Type - Known Parameter - Unknown ParameterLoad Bus -P, Q - V, phase angleGenerator Bus - P, V (magnitude) - Q, Voltage phase angleSlack Bus Voltage - magnitude and phase angle - P, Q
MGVCL Exam Paper (30-07-2021 Shift 3) A single phase motor connected to 400 V, 50 Hz supply takes 25 A at a power factor of 0.75 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.95 lagging. 82.55 pF 92.55 pF 62.55 pF 72.55 pF 82.55 pF 92.55 pF 62.55 pF 72.55 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For single phase induction motor,P = V*I*cosφ= 400*25*0.75= 7500 WQ1 = P*tan(φ) = 7500*0.80= 6015 VARNow power factor change to 0.95So, φ' = 25.84 degreeQ = 7500*tan(18.19)= 2464.424Qnet = Q - Q'= 6015 - 2464.424= 4500.8C = V²/(2*ᴨ*f*Q)= (400*400)/(2*ᴨ*50*3575.76)= 8.255*10^(-5)= 82.55 μF
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