MGVCL Exam Paper (30-07-2021 Shift 3) In public sector, what is the full form of "LIC"? Life Insurance Corporation Life Insurance Company Lively Insurance Corporation Life Insurers Life Insurance Corporation Life Insurance Company Lively Insurance Corporation Life Insurers ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) If a cable of homogeneous insulation has maximum stress of 6 kV/mm, then the dielectric strength of insulation should be ____ 1.5 kV/mm 12 kV/mm 3 kV/mm 6 kv/mm 1.5 kV/mm 12 kV/mm 3 kV/mm 6 kv/mm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP If a cable have homogeneous insulation then the dielectric strength of insulation should be is equal to maximum dielectric strength.
MGVCL Exam Paper (30-07-2021 Shift 3) A 3 pF capacitor is charged by a constant current of 2 pA for six seconds. The voltage across the capacitor at the end of charging will be 4 V 2 V 8 V 6 V 4 V 2 V 8 V 6 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation know that the charge stored in a capacitor is given as:Q = C*VQ = I*tV = (I*t)/C= (2μ*6)/(3μ)= 4 V
MGVCL Exam Paper (30-07-2021 Shift 3) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 2 hours. What is the permissible overload for a duration of two hours. Assume the permissible load kVA as a fraction of rated kVA is 1.43. 715 kVA 700 kVA 1430 kVA 1050 kVA 715 kVA 700 kVA 1430 kVA 1050 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload for transformer = Full load kVA*factor for permissible overload= 1000*1.43= 1430 kVA
MGVCL Exam Paper (30-07-2021 Shift 3) A single phase full converter bridge, connected to 230 V, 50 Hz source is feeding a load R =10 Ω in series with a large inductance that makes the load current ripple free. For a firing angle of 450, calculate the rectification efficiency. 63.66% 28.33% 76.66% 50.55% 63.66% 28.33% 76.66% 50.55% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rectification efficiency = DC output power/AC input power
MGVCL Exam Paper (30-07-2021 Shift 3) A DC shunt generator has an induced voltage of 220 V on open circuit. When the machine is on load the terminal voltage is 200 V. Find the load current if the field resistance is 100 Ω and armature resistance is 0.2 Ω. 98 A 104 A 96 A 102 A 98 A 104 A 96 A 102 A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Voltage equation for Dc shunt generator,Eb = V + Ia*RaV = Ish*RshIsh = 200/100= 2 AEb = V + Ia*Ra20 = Ia*RaIa = 20/0.2= 100 AI = 100 - 2= 98 A
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