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MGVCL Exam Paper (30-07-2021 Shift 3)

MGVCL Exam Paper (30-07-2021 Shift 3)
The current in the coil of a large electromagnet falls from 6 A to 2 A in 10 ms. The induced emf across the coil is 100 V. Find the self-inductance of the coil.

0.25 H
1.25 H
0.5 H
0.75 H

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Equation of self inductance:
V = Ls*(di/dt)
Ls = V/(di/dt)
= 100/((6 - 2)/(0.01))
= 0.250 H
= 250 mH

MGVCL Exam Paper (30-07-2021 Shift 3)
Transistors were used in

Second Generation Computers
First Generation Computers
Third Generation Computers
Fourth Generation Computers

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MGVCL Exam Paper (30-07-2021 Shift 3)
If the phase velocity of a plane wave in a perfect dielectric is 0.4 times its value in free space, then what is the relative permittivity of the dielectric?

6.25
4.25
2.5
1.25

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The equation is given by:
Vp (Phase velocity) = (Velocity of light in free space/Phase velocity)²
= (1/0.4)²
= 6.25

MGVCL Exam Paper (30-07-2021 Shift 3)
Choose the word which expresses nearly the opposite meaning of the given word "DILIGENT "

Active
Busy
Careful
Lasy

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
Data Encryption Standard (DES) was designed by

Apple
IBM
Microsoft
None of these

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MGVCL Exam Paper (30-07-2021 Shift 3)
A three phase four pole 50 Hz induction motor has a rotor resistance of 0.02 Ω/phase and stand-still reactance of 0.5 Ω/phase. Calculate the speed at which the maximum torque is developed.

1525 rpm
1440 rpm
1475 rpm
1500 rpm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Condition for maximum torque,
Sm = R2/X2
= 0.04
Ns = (120*f)/P
= (120*50)/4
= 1500 rpm
S = (Ns - Nr)/Ns
Nr = Ns(1 - Sm)
= 1500*(1 - 0.04)
= 1440 rpm

MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 3)

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