MGVCL Exam Paper (30-07-2021 Shift 3)
The current in the coil of a large electromagnet falls from 6 A to 2 A in 10 ms. The induced emf across the coil is 100 V. Find the self-inductance of the coil.
Die-electric test on Circuit breaker: These tests are performed to check power frequency and impulse voltage withstand capacity. Power frequency tests are kept on a new circuit breaker, the test voltage changes with a circuit breaker rated voltage. In impulse tests, impulse voltage of particular value is employed to the breaker.
In this type of tariff, The total charge is divided into two components: fixed charges and running charges. The fixed charges depend upon the number of units consumed by the consumer. It can be expressed as Total Cost = [A (kW) + B (kWh)] Rs. A = charge per kW of max demand (A is a constant which when multiplied with max demand (kW) gives the total fixed costs.) B = charge per kWh of energy consumed (B is a constant which when multiplied with units consumed (kWh), gives total running charges.)
1.6 inches = 1.6 inches x 1,000 mils per inch = 1,600 mils 0.25 inch = 0.25 inch x 1,000 mils per inch = 250 mils Area = 1,600 x 250 = 400,000 square mils
EXAMIANS