MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? You can place as many access lists as you want on any interface until you run out of memory. One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can apply only one access list on any interface You can apply two access lists to any interface You can place as many access lists as you want on any interface until you run out of memory. One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can apply only one access list on any interface You can apply two access lists to any interface ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The Great Barrier Reef is located in which country? Germany Australia Canada India Germany Australia Canada India ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? In the cables, sheaths are used to provide enough strength. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. The current carrying capacity of cables in DC is less than that in AC. In the cables, sheaths are used to provide enough strength. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. The current carrying capacity of cables in DC is less than that in AC. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) શિક્ષકે વિદ્યાર્થીને વાર્તા કહી'1. વાક્ય અક્મર્ક છે.2. વાક્ય દ્રીકર્મક છે.3. વાક્યમાં વિદ્યાર્થીને 'પ્રધાન કર્મ' છે અને વાર્તા 'ગૌણ કર્મ' છે.4.વાક્યમાં વાર્તાને 'પ્રધાન કર્મ' છે અને વિધાથીને 'ગૌણ કર્મ' છે 2,4 2,3 1,3 1,3 2,4 2,3 1,3 1,3 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The line currents in amperes in phases a, b and c respectively are 500 +j150, 100 – j600 and – 300 + j600 referred to the same reference vector with phase sequence of abc. Find the symmetrical component of currents. Ia₀ = (100+j50) AIa₁ = (546.41+j165.47) AIa₂ = (-146.41-j65.47) A Ia₀ = (100+j50) AIa₁ = (546.41+ j165.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (146.41+ j65.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (200+ j107.75) AIa₂ = (200-j107.75) A Ia₀ = (100+j50) AIa₁ = (546.41+j165.47) AIa₂ = (-146.41-j65.47) A Ia₀ = (100+j50) AIa₁ = (546.41+ j165.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (146.41+ j65.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (200+ j107.75) AIa₂ = (200-j107.75) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Calculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 500 + j150 + (- 0.5 + j*0.866)*(100 – j6000) + (-0.5 - j*0.866)*(– 300 + j600)= (546.41 + j*156.47) AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= 500 + j150 + (- 0.5 - j*0.866)*(100 – j6000) + (-0.5 + j*0.866)*(– 300 + j600)= (-146.41 - j*56.47) AIao = 1/3*(Ia + Ib + Ic)= 1/3*(500 + j150 + 100 – j6000 – 300 + j600)= (100 + j*50) A
MGVCL Exam Paper (30-07-2021 Shift 2) In the RLC series circuit shown in figure, resonance occurs when the value of C is 20 µF. The supply voltages is v(t) = 20 sin (500t) V. Find the value of L. 5 H 5 mH 0.2 H 0.2 mH 5 H 5 mH 0.2 H 0.2 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,ω = 500 rad/sec = 2πf.At Resonance condition,ωL = 1/(ωC)L 0.2 HAlso at series resonace1. fr = 1/[2π√(LC)]2. PF = 13. Maximum current4. Source voltage = voltage across resistor.
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