MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface You can apply two access lists to any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface You can apply two access lists to any interface ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. The current carrying capacity of cables in DC is less than that in AC. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, sheaths are used to provide enough strength. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. The current carrying capacity of cables in DC is less than that in AC. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, sheaths are used to provide enough strength. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) A circuit breaker is rated 2500 A, 2000 MVA, 33 kV, 3 sec, 3-phase oil circuit breaker. Determine the breaking current. 350 kA 35 kA 2500 A 25 kA 350 kA 35 kA 2500 A 25 kA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breaking capacity of circuit breaker = √3*VL*IbVL - line voltage in voltIL - Line current/breaking in ampereVL = 33 kVS = 2000 MVAIb = 30*1000 (in kVA)/(√3*33)Ib = 34.99 kA
MGVCL Exam Paper (30-07-2021 Shift 2) Fill in the blanks with suitable Article from the given alternatives.I heard ____interesting story yesterday a the an No article a the an No article ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 75 km to 100 km 20 to 25 km 30 km to 60 km 10 km to 15 km 75 km to 100 km 20 to 25 km 30 km to 60 km 10 km to 15 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is E = Vx(d)² E = V/(d)² E = V x d E = V/d E = Vx(d)² E = V/(d)² E = V x d E = V/d ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is given by:V = E*LE = V/L
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