MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Abolishid Oscillate seriuous Socialy Abolishid Oscillate seriuous Socialy ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Vikram Seth is associated with which of the following fields? Politician Literature Music Sports Politician Literature Music Sports ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance. (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + IXsinφ)/V_rFor leading power factor = (IR*cosφ - IXsinφ)/V_rZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 2) If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be 9 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s 27 × 10⁸ m/s 9 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s 27 × 10⁸ m/s ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Speed of EM wave in medium = C/√(εr*μr)= (300000000)/√9= 300000000/3= 100000000= 1*10⁸ m/s
MGVCL Exam Paper (30-07-2021 Shift 2) Choose the word which expresses nearly the opposite meaning of the given word "WHIMSICAL" Curious Funny Regular Fantastic Curious Funny Regular Fantastic ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series opposing. 730 mH 1135 mH 1270 mH 932 mH 730 mH 1135 mH 1270 mH 932 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP M = k√(L₁L₂)M= 0.45√(100*900)M = 135 mHL_eq for opposite connection of coils = L₁ + L₂ - 2ML_eq = 900 + 100 - 2*135L_eq = 730 mH
EXAMIANS