MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Abolishid seriuous Oscillate Socialy Abolishid seriuous Oscillate Socialy ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, sheaths are used to provide enough strength. The current carrying capacity of cables in DC is less than that in AC. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, sheaths are used to provide enough strength. The current carrying capacity of cables in DC is less than that in AC. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors).(A) The Manager, with / (B) all his employee, was / (C) fired from the company /(D) NO ERROR A B D C A B D C ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following is the committee on poverty estimation? S.S.Tarapore committee Tendulkar committee Ad hoc committe Karve committee S.S.Tarapore committee Tendulkar committee Ad hoc committe Karve committee ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 1240 kVA 930 kVA 620 kVA 2480 kVA 1240 kVA 930 kVA 620 kVA 2480 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA
MGVCL Exam Paper (30-07-2021 Shift 2) Vikram Seth is associated with which of the following fields? Politician Sports Music Literature Politician Sports Music Literature ANSWER DOWNLOAD EXAMIANS APP
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