MGVCL Exam Paper (30-07-2021 Shift 2) નીચે પૈકી કયો 'દાદુર' નો સમાનર્થી નથી દેડકો દર્દુર મેડક સુમાર દેડકો દર્દુર મેડક સુમાર ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) શિક્ષકે વિદ્યાર્થીને વાર્તા કહી'1. વાક્ય અક્મર્ક છે.2. વાક્ય દ્રીકર્મક છે.3. વાક્યમાં વિદ્યાર્થીને 'પ્રધાન કર્મ' છે અને વાર્તા 'ગૌણ કર્મ' છે.4.વાક્યમાં વાર્તાને 'પ્રધાન કર્મ' છે અને વિધાથીને 'ગૌણ કર્મ' છે 2,4 1,3 1,3 2,3 2,4 1,3 1,3 2,3 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Transistors were used in ____ of Computers. Fourth Generation Third Generation First Generation Second Generation Fourth Generation Third Generation First Generation Second Generation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In the circuit shown in figure, the voltage across 8 Ω resistor is 20 V. Calculate the supply voltage. 47 V 38 V 18 V 27 V 47 V 38 V 18 V 27 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equivalent resistance of the circuit,Req = (12||18) + 8Req = 7.2 + 8Req = 15.2 ohmSource current = current through 8 ohm resistor, I = Vr/R8I = 20/8I = 2.5 ASupply votage V = I*ReqV = 2.5*15.2V = 38 V
MGVCL Exam Paper (30-07-2021 Shift 2) A circuit breaker is rated 2500 A, 2000 MVA, 33 kV, 3 sec, 3-phase oil circuit breaker. Determine the breaking current. 350 kA 35 kA 25 kA 2500 A 350 kA 35 kA 25 kA 2500 A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breaking capacity of circuit breaker = √3*VL*IbVL - line voltage in voltIL - Line current/breaking in ampereVL = 33 kVS = 2000 MVAIb = 30*1000 (in kVA)/(√3*33)Ib = 34.99 kA
MGVCL Exam Paper (30-07-2021 Shift 2) The line currents in amperes in phases a, b and c respectively are 500 +j150, 100 – j600 and – 300 + j600 referred to the same reference vector with phase sequence of abc. Find the symmetrical component of currents. Ia₀ = (100+j50) AIa₁ = (146.41+ j65.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (546.41+j165.47) AIa₂ = (-146.41-j65.47) A Ia₀ = (100+j50) AIa₁ = (200+ j107.75) AIa₂ = (200-j107.75) A Ia₀ = (100+j50) AIa₁ = (546.41+ j165.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (146.41+ j65.47) AIa₂ = (546.41-j165.47) A Ia₀ = (100+j50) AIa₁ = (546.41+j165.47) AIa₂ = (-146.41-j65.47) A Ia₀ = (100+j50) AIa₁ = (200+ j107.75) AIa₂ = (200-j107.75) A Ia₀ = (100+j50) AIa₁ = (546.41+ j165.47) AIa₂ = (546.41-j165.47) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Calculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 500 + j150 + (- 0.5 + j*0.866)*(100 – j6000) + (-0.5 - j*0.866)*(– 300 + j600)= (546.41 + j*156.47) AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= 500 + j150 + (- 0.5 - j*0.866)*(100 – j6000) + (-0.5 + j*0.866)*(– 300 + j600)= (-146.41 - j*56.47) AIao = 1/3*(Ia + Ib + Ic)= 1/3*(500 + j150 + 100 – j6000 – 300 + j600)= (100 + j*50) A
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