MGVCL Exam Paper (30-07-2021 Shift 2) નીચે પૈકી કયો 'દાદુર' નો સમાનર્થી નથી મેડક સુમાર દેડકો દર્દુર મેડક સુમાર દેડકો દર્દુર ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? You can apply only one access list on any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can apply two access lists to any interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can apply two access lists to any interface You can place as many access lists as you want on any interface until you run out of memory. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circuit breaker is rated 2500 A, 2000 MVA, 33 kV, 3 sec, 3-phase oil circuit breaker. Determine the breaking current. 35 kA 25 kA 2500 A 350 kA 35 kA 25 kA 2500 A 350 kA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breaking capacity of circuit breaker = √3*VL*IbVL - line voltage in voltIL - Line current/breaking in ampereVL = 33 kVS = 2000 MVAIb = 30*1000 (in kVA)/(√3*33)Ib = 34.99 kA
MGVCL Exam Paper (30-07-2021 Shift 2) A sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity is called as Oscillatory transients Harmonic Impulsive transient Distortion Oscillatory transients Harmonic Impulsive transient Distortion ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Oscillatory transient is the a sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity.
MGVCL Exam Paper (30-07-2021 Shift 2) In the circuit of figure, the switch is closed to position-1 for a long time. At t = 0 the switch position is changed from postion-1 to postion-2. Find an expression for the current i(t). i(t) = (E/R) sin√(LC) t A i(t) = (E/R) cos√(LC) t A i(t) = (E/R) sin[1/√(LC)]t A i(t) = (E/R) cos[1/√(LC)]t A i(t) = (E/R) sin√(LC) t A i(t) = (E/R) cos√(LC) t A i(t) = (E/R) sin[1/√(LC)]t A i(t) = (E/R) cos[1/√(LC)]t A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Standard eqution of current for this condition,i(t) = i(0+)*cos(wt)i(0+) = E/RFor LC circuit,w = 1/√(LC)i(t) = (E/R)*cos((1/√(LC))*t) A
MGVCL Exam Paper (30-07-2021 Shift 2) પાણી : પાણીગ્રહણ :: હસ્ત : ??? પ્રેમાલાપ છુટાછેડા હસ્તમેળાપ વિવાહ પ્રેમાલાપ છુટાછેડા હસ્તમેળાપ વિવાહ ANSWER DOWNLOAD EXAMIANS APP
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