MGVCL Exam Paper (30-07-2021 Shift 2) નીચે પૈકી કયો 'દાદુર' નો સમાનર્થી નથી સુમાર દર્દુર મેડક દેડકો સુમાર દર્દુર મેડક દેડકો ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circular loop has its radius increasing at a rate of 2 m/s. The loop is placed perpendicular to a constant magnetic field of 0.1 Wb/m². When the radius of the loop is 2 m, the emf induced in the loop will be zero 0.8π V 0.4π V 0.2π V zero 0.8π V 0.4π V 0.2π V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP emf = dΨ/dt = change of flux linkageemf = dф/dtemf = d(B*Area)/dtemf = B*d(area)/dtemf = B*d(πr²)/dtemf = Bπ*2r*dr/dtemf = Bπ*2r*change of radius per unit timeemf = 0.1*π*2*2emf = 4π
MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Assert in Dander Syndrome Acquire in Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquired Immune Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquired Immune Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 12 kV, 50 Hz and 300 kW load is operating at 0.8 pf lag. If the pf is to be improved to unity, using star connected capacitor, the per phase value of the reactive VAR required is: 75 kVAR 100 kVAR 25 kVAR 50 kVAR 75 kVAR 100 kVAR 25 kVAR 50 kVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The reactive VAR required = kW*(tanφ1 -tanφ2)Cosφ1 = 0.8φ1 = 36.87 deg.Cosφ2 = 0φ2 = 0 deg.kVAR required = kW*(tan(36.87) - tan(0))= 300*1000(0.75)= 225.00 kVARPer phase value = 225.00/3= 75 kVAR
MGVCL Exam Paper (30-07-2021 Shift 2) When different types of consumers are charged at different uniform per unit rates, it is called as ____ two-part tariff block rate tariff maximum demand tariff flat rate tariff two-part tariff block rate tariff maximum demand tariff flat rate tariff ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When different types of consumers are charged at different uniform per unit rates, it is said to be Flat Rate Tariff.In this type, the consumers are grouped into different classes.Each class is charged at different uniform rate.
MGVCL Exam Paper (30-07-2021 Shift 2) A short-shunt dc compound generator supplies 50 A at 300 V. If the shunt field resistance, series field resistance and armature resistance are 30 Ω, 0.03Ω, and 0.05 Ω respectively, determine the e.m.f. generated. 304.5 V 306.5 V 302.5 V 308.5 V 304.5 V 306.5 V 302.5 V 308.5 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Vt = 300 VRse = 0.03 Ω, Rsh = 30 Ω, Ra = 0.05 ΩI_L = 50 AVsh = V + I_L*Rse = 300 + 50*0.03 = 301.5 VIsh = Vsh/Rsh = 301.5/30 = 10.05 AIa = Ish + I_L = 60.05 AEg = Vt + I_L*Rse + IaRaEg = 300 + 50*0.03 + 60.05*0.05 = 304.5025 V
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