MGVCL Exam Paper (30-07-2021 Shift 2) Operating system is a program that runs during log off a program that runs during log off a program that runs for short duration a layer between the user and the hardware a program that runs during log off a program that runs during log off a program that runs for short duration a layer between the user and the hardware ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Transistors were used in ____ of Computers. Third Generation Fourth Generation First Generation Second Generation Third Generation Fourth Generation First Generation Second Generation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is E = Vx(d)² E = V/(d)² E = V x d E = V/d E = Vx(d)² E = V/(d)² E = V x d E = V/d ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is given by:V = E*LE = V/L
MGVCL Exam Paper (30-07-2021 Shift 2) The Great Barrier Reef is located in which country? Canada Australia India Germany Canada Australia India Germany ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) 1. આપને મુખ્યમત્રીએ ખાસ કામ માટે નિયુક્ત કર્યા છે.2. તેનાથી આંખો ઝીણી કરાઈ3. પ્રધાનમંત્રીએ સ્કુલનું ઉદ્રઘાટન કર્યું.આરોપીએ બધા ગુના કબુલ કરી લીધા.ઉક્ત વાક્યોમાં કેટલા કર્મણી વાક્યો પ્રયોગના છે? બધા જ કર્તરી વાક્ય પ્રયોગના છે કુલ 1 કુલ 2 બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે બધા જ કર્તરી વાક્ય પ્રયોગના છે કુલ 1 કુલ 2 બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter. W1 = 10 kW and W2 = 20 kW W1 = -10 kW and W2 = 40 kW W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = 10 kW and W2 = 20 kW W1 = -10 kW and W2 = 40 kW W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Cosφ = 0.397P = 30 kW = √3*V_L*I_L*cosφV_L*I_L = 30kW/(√3*0.397) = 43628.48 VAReadings of wattmeter W1 = V_L*I_L*cos(30+φ)Readings of wattmeter W2 = V_L*I_L*cos(30-φ)
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