MGVCL Exam Paper (30-07-2021 Shift 2) The wind speed increases with height because of reduction in the gravitational force reduction in lift effect of the air reduction of drag effect of the earth surface enhancement of drag effect on the earth surface reduction in the gravitational force reduction in lift effect of the air reduction of drag effect of the earth surface enhancement of drag effect on the earth surface ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Wind speed increases as the height from the ground increases mainly due to the decrease in the friction produced by land terrain.
MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Abolishid Oscillate Socialy seriuous Abolishid Oscillate Socialy seriuous ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following is the largest windfarm located in India? Muppandal Vindhayachal Mundra Talcher Muppandal Vindhayachal Mundra Talcher ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rank - Windfarm name - Capacity1 - Muppandal windfarm - 1500 MW2 - Jaisalmer Wind Park - 1064 MW3 - Brahmanvel Wind Farm Dhule - 964 MW4 - Damanjodi Wind Farm - 99 MW5 - Tuppadahalli Wind Farm - 56.1 MW
MGVCL Exam Paper (30-07-2021 Shift 2) શિક્ષકે વિદ્યાર્થીને વાર્તા કહી'1. વાક્ય અક્મર્ક છે.2. વાક્ય દ્રીકર્મક છે.3. વાક્યમાં વિદ્યાર્થીને 'પ્રધાન કર્મ' છે અને વાર્તા 'ગૌણ કર્મ' છે.4.વાક્યમાં વાર્તાને 'પ્રધાન કર્મ' છે અને વિધાથીને 'ગૌણ કર્મ' છે 1,3 2,4 1,3 2,3 1,3 2,4 1,3 2,3 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is linux operating system? MacOS IBM-AIX Fedora HP-UX MacOS IBM-AIX Fedora HP-UX ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.3 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.62 Hz 1.42 Hz 1.32 Hz 1.52 Hz 1.62 Hz 1.42 Hz 1.32 Hz 1.52 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (11/05)*cosδ= (11/0.5)*0.5M = (H*s)/(πf)= 4/(50π)fn = (1.76*(3/50π))= 9.4 rad/sec = 1.32 Hz