MGVCL Exam Paper (30-07-2021 Shift 2) The wind speed increases with height because of enhancement of drag effect on the earth surface reduction of drag effect of the earth surface reduction in lift effect of the air reduction in the gravitational force enhancement of drag effect on the earth surface reduction of drag effect of the earth surface reduction in lift effect of the air reduction in the gravitational force ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Wind speed increases as the height from the ground increases mainly due to the decrease in the friction produced by land terrain.
MGVCL Exam Paper (30-07-2021 Shift 2) પાણી : પાણીગ્રહણ :: હસ્ત : ??? પ્રેમાલાપ હસ્તમેળાપ છુટાછેડા વિવાહ પ્રેમાલાપ હસ્તમેળાપ છુટાછેડા વિવાહ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is an application layer service? Mail service Mail service Network virtual terminal File transfer, access and management Mail service Mail service Network virtual terminal File transfer, access and management ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A THHN conductor will have a 60˚C termination on one end and a 75˚C termination on the other, which ampacity column will be used? 75˚C column 90˚C column 60˚C column None of these 75˚C column 90˚C column 60˚C column None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Conductor with higher temperature ratings, provide the ampacity is determined based on the 60°C ampacity of the conductor.
MGVCL Exam Paper (30-07-2021 Shift 2) આપને કાઈ મશીન નથી કે અમુક ગોઠવણો પ્રમાણે કાર્ય જ કરીએ. - ઉપરોક્ત વાક્ય જુદાં પાડવા ક્યાં સંયોજકો કાઢવા પડે. કે કાઈ અમુક જ કે કાઈ અમુક જ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 12 kV, 50 Hz and 300 kW load is operating at 0.8 pf lag. If the pf is to be improved to unity, using star connected capacitor, the per phase value of the reactive VAR required is: 75 kVAR 50 kVAR 100 kVAR 25 kVAR 75 kVAR 50 kVAR 100 kVAR 25 kVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The reactive VAR required = kW*(tanφ1 -tanφ2)Cosφ1 = 0.8φ1 = 36.87 deg.Cosφ2 = 0φ2 = 0 deg.kVAR required = kW*(tan(36.87) - tan(0))= 300*1000(0.75)= 225.00 kVARPer phase value = 225.00/3= 75 kVAR
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