MGVCL Exam Paper (30-07-2021 Shift 2) Tree Topology Paper size Web layout Page Orientation Font style Paper size Web layout Page Orientation Font style ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Sentimant Absurrd Maximum Wrinkel Sentimant Absurrd Maximum Wrinkel ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) હુ ગીત ગાઈશ' ને કર્મણીમાં ફેરવો. મારાથી ગીત ગવાશે ગીતને હુ જ ગાઇશ હુ ગીતને ગાઈશ ગીતને હુ ગાઈશ મારાથી ગીત ગવાશે ગીતને હુ જ ગાઇશ હુ ગીતને ગાઈશ ગીતને હુ ગાઈશ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be 1 × 10⁸ m/s 27 × 10⁸ m/s 3 × 10⁸ m/s 9 × 10⁸ m/s 1 × 10⁸ m/s 27 × 10⁸ m/s 3 × 10⁸ m/s 9 × 10⁸ m/s ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Speed of EM wave in medium = C/√(εr*μr)= (300000000)/√9= 300000000/3= 100000000= 1*10⁸ m/s
MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 20 to 25 km 30 km to 60 km 10 km to 15 km 75 km to 100 km 20 to 25 km 30 km to 60 km 10 km to 15 km 75 km to 100 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is E = V/(d)² E = V/d E = Vx(d)² E = V x d E = V/(d)² E = V/d E = Vx(d)² E = V x d ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is given by:V = E*LE = V/L
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