MGVCL Exam Paper (30-07-2021 Shift 2) Tree Topology Font style Web layout Paper size Page Orientation Font style Web layout Paper size Page Orientation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) 1. આપને મુખ્યમત્રીએ ખાસ કામ માટે નિયુક્ત કર્યા છે.2. તેનાથી આંખો ઝીણી કરાઈ3. પ્રધાનમંત્રીએ સ્કુલનું ઉદ્રઘાટન કર્યું.આરોપીએ બધા ગુના કબુલ કરી લીધા.ઉક્ત વાક્યોમાં કેટલા કર્મણી વાક્યો પ્રયોગના છે? કુલ 2 બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે કુલ 1 બધા જ કર્તરી વાક્ય પ્રયોગના છે કુલ 2 બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે કુલ 1 બધા જ કર્તરી વાક્ય પ્રયોગના છે ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The necessary equation to be solved during the load flow analysis using Fast-Decoupled method is given below:where B' and B'' are formed using the imaginary part of the bus admittance matrix, Ybus. If the system consists of 6 buses of which one of the bus is slack bus and 2 bues are voltage regulated buses, then then the matrix B' is of order ____and the matrix B'' is of order____, respectivity.∆P/|Vi| = - B'∆δ∆Q/|Vi| = - B''∆|V| 5 and 3 6 and 3 3 and 6 3 and 5 5 and 3 6 and 3 3 and 6 3 and 5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In Fast-decoupled method,Order of B' = No. of PV buses = 5Order of B'' = No. of PQ buses = 3
MGVCL Exam Paper (30-07-2021 Shift 2) Transistors were used in ____ of Computers. Second Generation Third Generation First Generation Fourth Generation Second Generation Third Generation First Generation Fourth Generation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter. W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = 10 kW and W2 = 20 kW W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = 10 kW and W2 = 20 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Cosφ = 0.397P = 30 kW = √3*V_L*I_L*cosφV_L*I_L = 30kW/(√3*0.397) = 43628.48 VAReadings of wattmeter W1 = V_L*I_L*cos(30+φ)Readings of wattmeter W2 = V_L*I_L*cos(30-φ)
MGVCL Exam Paper (30-07-2021 Shift 2) In a synchronous motor with field under excited, the power factor will be lagging leading unity zero lagging leading unity zero ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For synchronous motor,Under excitation - Lagging power factorOver excitation - Leading power factorFor synchronous generatorUnder excitation - Leading power factorOver excitation - lagging power factor