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MGVCL Exam Paper (30-07-2021 Shift 2)

MGVCL Exam Paper (30-07-2021 Shift 2)
Encrypted security payload extension header is new in

IP
IPv5
IPv6
IPv4

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MGVCL Exam Paper (30-07-2021 Shift 2)
If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be

27 × 10⁸ m/s
9 × 10⁸ m/s
1 × 10⁸ m/s
3 × 10⁸ m/s

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Speed of EM wave in medium = C/√(εr*μr)
= (300000000)/√9
= 300000000/3
= 100000000
= 1*10⁸ m/s

MGVCL Exam Paper (30-07-2021 Shift 2)
If all the devices are connected to a central hub, then the topology is called

Tree Topology
Tree Topology
Bus Topology
Star Topology

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MGVCL Exam Paper (30-07-2021 Shift 2)
In a synchronous motor with field under excited, the power factor will be

zero
unity
lagging
leading

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

For synchronous motor,
Under excitation - Lagging power factor
Over excitation - Leading power factor

For synchronous generator
Under excitation - Leading power factor
Over excitation - lagging power factor

MGVCL Exam Paper (30-07-2021 Shift 2)
In the circuit shown in figure, the voltage across 8 Ω resistor is 20 V. Calculate the supply voltage.

18 V
27 V
47 V
38 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Equivalent resistance of the circuit,
Req = (12||18) + 8
Req = 7.2 + 8
Req = 15.2 ohm
Source current = current through 8 ohm resistor, I = Vr/R8
I = 20/8
I = 2.5 A
Supply votage V = I*Req
V = 2.5*15.2
V = 38 V

MGVCL Exam Paper (30-07-2021 Shift 2)
The operating time of an inverse definite minimum time (IDMT) overcurrent relay is ____ proportional to the plug-setting multiplier (PSM) and____proportional to the time-multiplier setting (TMS).

inversely, directly
inversely, inversely
directly, directly
directly, inversely

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MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 2)

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