MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is an application layer service? Mail service Mail service File transfer, access and management Network virtual terminal Mail service Mail service File transfer, access and management Network virtual terminal ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.3 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.52 Hz 1.42 Hz 1.32 Hz 1.62 Hz 1.52 Hz 1.42 Hz 1.32 Hz 1.62 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (11/05)*cosδ= (11/0.5)*0.5M = (H*s)/(πf)= 4/(50π)fn = (1.76*(3/50π))= 9.4 rad/sec = 1.32 Hz
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. The current carrying capacity of cables in DC is less than that in AC. In the cables, sheaths are used to provide enough strength. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. The current carrying capacity of cables in DC is less than that in AC. In the cables, sheaths are used to provide enough strength. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 10 km to 15 km 20 to 25 km 30 km to 60 km 75 km to 100 km 10 km to 15 km 20 to 25 km 30 km to 60 km 75 km to 100 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase motor connected to 415 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging. 86.32 µF 76.32 µF 96.32 µF 66.32 µF 86.32 µF 76.32 µF 96.32 µF 66.32 µF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = VIcosφ = 8715 wattQ = VAR required to improve PF = P(tanφ₁ - tanφ₂) = 4670 VARCapacitive Reactance, Xc = V²/Q = 36.8790 ohm.C = (2πfXc)⁻¹ = 86.314 μF
MGVCL Exam Paper (30-07-2021 Shift 2) In the context of smart meters, the term 'SMETS' stand for Smart Monitoring Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Standard Metering Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Standard Metering Equipment Technical Specifications ANSWER DOWNLOAD EXAMIANS APP
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