MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Maximum Absurrd Wrinkel Sentimant Maximum Absurrd Wrinkel Sentimant ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A generating station having 'n' section busbars each rated at Q kVA with ×% reactance is connected on the tie-bars systems through busbar reactances of b%. Determine the short circuit kVA if a 3-phase fault takes place on one section. Q[(1/x) + (n-1)/(bn+x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) - (n+1)/(bn-x)] Q[(1/x) + (n-1)/(bn+x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) - (n+1)/(bn-x)] ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Short circuit kVA of any bus is given by:Skva = Sbase*(100/% X)Where,Sbase - base rating in kVA% X - value of reactance in %
MGVCL Exam Paper (30-07-2021 Shift 2) The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance. (IRcosφ_r + IXsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + IXsinφ)/V_rFor leading power factor = (IR*cosφ - IXsinφ)/V_rZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 2) A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter. W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = 10 kW and W2 = 20 kW W1 = -10 kW and W2 = 40 kW W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = 10 kW and W2 = 20 kW W1 = -10 kW and W2 = 40 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Cosφ = 0.397P = 30 kW = √3*V_L*I_L*cosφV_L*I_L = 30kW/(√3*0.397) = 43628.48 VAReadings of wattmeter W1 = V_L*I_L*cos(30+φ)Readings of wattmeter W2 = V_L*I_L*cos(30-φ)
MGVCL Exam Paper (30-07-2021 Shift 2) In a synchronous motor with field under excited, the power factor will be leading lagging unity zero leading lagging unity zero ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For synchronous motor,Under excitation - Lagging power factorOver excitation - Leading power factorFor synchronous generatorUnder excitation - Leading power factorOver excitation - lagging power factor
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? You can apply only one access list on any interface You can apply two access lists to any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface You can apply two access lists to any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. ANSWER DOWNLOAD EXAMIANS APP
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