MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. The current carrying capacity of cables in DC is less than that in AC. In the cables, sheaths are used to provide enough strength. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. The current carrying capacity of cables in DC is less than that in AC. In the cables, sheaths are used to provide enough strength. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Amino Intersect Deficiency Syndrome Acquire in Deficiency Syndrome Assert in Dander Syndrome Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquire in Deficiency Syndrome Assert in Dander Syndrome Acquired Immune Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? You can apply two access lists to any interface You can apply only one access list on any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply two access lists to any interface You can apply only one access list on any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series opposing. 730 mH 1270 mH 932 mH 1135 mH 730 mH 1270 mH 932 mH 1135 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP M = k√(L₁L₂)M= 0.45√(100*900)M = 135 mHL_eq for opposite connection of coils = L₁ + L₂ - 2ML_eq = 900 + 100 - 2*135L_eq = 730 mH
MGVCL Exam Paper (30-07-2021 Shift 2) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors).(A) The Manager, with / (B) all his employee, was / (C) fired from the company /(D) NO ERROR B D C A B D C A ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is E = Vx(d)² E = V/d E = V/(d)² E = V x d E = Vx(d)² E = V/d E = V/(d)² E = V x d ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The relation between electric intensity E, voltage applied V and the distance d between the plates of a parallel plate condenser is given by:V = E*LE = V/L
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