MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 4-pole, 50 Hz induction motor runs at 1425 rpm. Find out the percentage slip of the induction motor. 6% 3% 5% 4% 6% 3% 5% 4% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Slip, s = (Ns - Nr)/NsNs = 120f/PNs = 1500 rpms = (1500 - 1425)/1500s = 0.05%s = 5%
MGVCL Exam Paper (30-07-2021 Shift 2) In the context of smart meters, the term 'SMETS' stand for Standard Metering Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Standard Metering Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is a national organisation monitoring the doping control programme in sports in India? National Anti-Doping Agency Indian Anti-Doping Agency International Anti-Doping Protocol Primary Anti-Doping Agency National Anti-Doping Agency Indian Anti-Doping Agency International Anti-Doping Protocol Primary Anti-Doping Agency ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A THHN conductor will have a 60˚C termination on one end and a 75˚C termination on the other, which ampacity column will be used? 75˚C column 60˚C column 90˚C column None of these 75˚C column 60˚C column 90˚C column None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Conductor with higher temperature ratings, provide the ampacity is determined based on the 60°C ampacity of the conductor.
MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Abolishid Socialy seriuous Oscillate Abolishid Socialy seriuous Oscillate ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter. W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = 10 kW and W2 = 20 kW W1 = -5 kW and W2 = 35 kW W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = 10 kW and W2 = 20 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Cosφ = 0.397P = 30 kW = √3*V_L*I_L*cosφV_L*I_L = 30kW/(√3*0.397) = 43628.48 VAReadings of wattmeter W1 = V_L*I_L*cos(30+φ)Readings of wattmeter W2 = V_L*I_L*cos(30-φ)
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