MGVCL Exam Paper (30-07-2021 Shift 2) નીચે માંથી ક્યાં રુઢિપ્રયોગનો અર્થ 'છેતરવું' એવો થાય આડા ઉતરવું બે પાંદડે થવું હથેળીમાં ચાંદ દેખાડવો દસ મારવો આડા ઉતરવું બે પાંદડે થવું હથેળીમાં ચાંદ દેખાડવો દસ મારવો ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Replace the underlined phrase grammatically and conceptually with the help of the given options. If the given sentence is correct then select the option 'The given sentence is correct'.The HR will give an topic to test the ability of our employees for the new project will give a topic to testing the ability of will give a topic to test the ability of will gives a topic to test the ability of The given sentence is correct will give a topic to testing the ability of will give a topic to test the ability of will gives a topic to test the ability of The given sentence is correct ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 620 kVA 1240 kVA 930 kVA 2480 kVA 620 kVA 1240 kVA 930 kVA 2480 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA
MGVCL Exam Paper (30-07-2021 Shift 2) A sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity is called as Distortion Oscillatory transients Harmonic Impulsive transient Distortion Oscillatory transients Harmonic Impulsive transient ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Oscillatory transient is the a sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity.
MGVCL Exam Paper (30-07-2021 Shift 2) In the circuit of figure, the switch is closed to position-1 for a long time. At t = 0 the switch position is changed from postion-1 to postion-2. Find an expression for the current i(t). i(t) = (E/R) cos√(LC) t A i(t) = (E/R) sin[1/√(LC)]t A i(t) = (E/R) sin√(LC) t A i(t) = (E/R) cos[1/√(LC)]t A i(t) = (E/R) cos√(LC) t A i(t) = (E/R) sin[1/√(LC)]t A i(t) = (E/R) sin√(LC) t A i(t) = (E/R) cos[1/√(LC)]t A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Standard eqution of current for this condition,i(t) = i(0+)*cos(wt)i(0+) = E/RFor LC circuit,w = 1/√(LC)i(t) = (E/R)*cos((1/√(LC))*t) A
MGVCL Exam Paper (30-07-2021 Shift 2) In a synchronous motor with field under excited, the power factor will be leading unity lagging zero leading unity lagging zero ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For synchronous motor,Under excitation - Lagging power factorOver excitation - Leading power factorFor synchronous generatorUnder excitation - Leading power factorOver excitation - lagging power factor
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