MGVCL Exam Paper (30-07-2021 Shift 2) નીચે માંથી ક્યાં રુઢિપ્રયોગનો અર્થ 'છેતરવું' એવો થાય હથેળીમાં ચાંદ દેખાડવો બે પાંદડે થવું દસ મારવો આડા ઉતરવું હથેળીમાં ચાંદ દેખાડવો બે પાંદડે થવું દસ મારવો આડા ઉતરવું ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) શિક્ષકે વિદ્યાર્થીને વાર્તા કહી'1. વાક્ય અક્મર્ક છે.2. વાક્ય દ્રીકર્મક છે.3. વાક્યમાં વિદ્યાર્થીને 'પ્રધાન કર્મ' છે અને વાર્તા 'ગૌણ કર્મ' છે.4.વાક્યમાં વાર્તાને 'પ્રધાન કર્મ' છે અને વિધાથીને 'ગૌણ કર્મ' છે 2,3 1,3 1,3 2,4 2,3 1,3 1,3 2,4 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Operating system is a program that runs for short duration a program that runs during log off a program that runs during log off a layer between the user and the hardware a program that runs for short duration a program that runs during log off a program that runs during log off a layer between the user and the hardware ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Match the following shown in figure A = (i) & (3) B = (ii) & (1) A = (iii) & (2) C = (ii) & (1) A = (i) & (3) B = (ii) & (1) A = (iii) & (2) C = (ii) & (1) ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series opposing. 932 mH 1135 mH 730 mH 1270 mH 932 mH 1135 mH 730 mH 1270 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP M = k√(L₁L₂)M= 0.45√(100*900)M = 135 mHL_eq for opposite connection of coils = L₁ + L₂ - 2ML_eq = 900 + 100 - 2*135L_eq = 730 mH
MGVCL Exam Paper (30-07-2021 Shift 2) The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance. (IRcosφ_r + IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + IXsinφ)/V_rFor leading power factor = (IR*cosφ - IXsinφ)/V_rZero voltage regulation occurs on leading power factor only.
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