MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is a national organisation monitoring the doping control programme in sports in India? National Anti-Doping Agency Primary Anti-Doping Agency International Anti-Doping Protocol Indian Anti-Doping Agency National Anti-Doping Agency Primary Anti-Doping Agency International Anti-Doping Protocol Indian Anti-Doping Agency ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be 3 × 10⁸ m/s 9 × 10⁸ m/s 27 × 10⁸ m/s 1 × 10⁸ m/s 3 × 10⁸ m/s 9 × 10⁸ m/s 27 × 10⁸ m/s 1 × 10⁸ m/s ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Speed of EM wave in medium = C/√(εr*μr)= (300000000)/√9= 300000000/3= 100000000= 1*10⁸ m/s
MGVCL Exam Paper (30-07-2021 Shift 2) In a synchronous motor with field under excited, the power factor will be unity zero leading lagging unity zero leading lagging ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For synchronous motor,Under excitation - Lagging power factorOver excitation - Leading power factorFor synchronous generatorUnder excitation - Leading power factorOver excitation - lagging power factor
MGVCL Exam Paper (30-07-2021 Shift 2) Operating system is a program that runs during log off a program that runs for short duration a layer between the user and the hardware a program that runs during log off a program that runs during log off a program that runs for short duration a layer between the user and the hardware a program that runs during log off ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase 240 V, 1 kW heater is connected across single phase 240 V, 50 Hz supply through an SCR. For firing angle delay of 90˚, calculate the power absorbed in the heater element. 300 W 225 W 250 W 275 W 300 W 225 W 250 W 275 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Resistance of heater, R = V²/PR = 57.6 ohmRMS value of voltage through controlled SCR = (Vm/2π)*(1 + cosα)= 120 VPower absorb by heater = Vrms²/R= 120²/57.6= 250 W
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