MGVCL Exam Paper (30-07-2021 Shift 2) In transformer, bushing failure occurs due to(i) transformer vibrations(ii) dielectric losses(ii) partial discharge (i) and (ii) only (i), (ii) and (iii) (i) and (iii) only (ii) and (iii) only (i) and (ii) only (i), (ii) and (iii) (i) and (iii) only (ii) and (iii) only ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Rearrange the following to form a meaningful sentence and find the most logical order from the given options.P: dancers make the companyQ: and they do not haveR: a big team of professionalS: a ‘guru shishya’ hierarchy RPSQ RPQS PQRS PQSR RPSQ RPQS PQRS PQSR ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circuit breaker is rated 2500 A, 2000 MVA, 33 kV, 3 sec, 3-phase oil circuit breaker. Determine the breaking current. 350 kA 35 kA 2500 A 25 kA 350 kA 35 kA 2500 A 25 kA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breaking capacity of circuit breaker = √3*VL*IbVL - line voltage in voltIL - Line current/breaking in ampereVL = 33 kVS = 2000 MVAIb = 30*1000 (in kVA)/(√3*33)Ib = 34.99 kA
MGVCL Exam Paper (30-07-2021 Shift 2) Encrypted security payload extension header is new in IPv5 IPv6 IP IPv4 IPv5 IPv6 IP IPv4 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Wrinkel Maximum Sentimant Absurrd Wrinkel Maximum Sentimant Absurrd ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 2480 kVA 620 kVA 930 kVA 1240 kVA 2480 kVA 620 kVA 930 kVA 1240 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA
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