MGVCL Exam Paper (30-07-2021 Shift 2) Who started the daily newspaper 'National Herald' in 1938? Jawaharlal Nehru Subhas Chandra Bose Ram Mohan Roy Dadabhai Naoroji Jawaharlal Nehru Subhas Chandra Bose Ram Mohan Roy Dadabhai Naoroji ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance. (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r (IRcosφ_r - IXsinφ_r)/V_r (IXcosφ_r + IRsinφ_r)/V_r (IXcosφ_r - IRsinφ_r)/V_r (IRcosφ_r + IXsinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + IXsinφ)/V_rFor leading power factor = (IR*cosφ - IXsinφ)/V_rZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 2) Replace the underlined phrase grammatically and conceptually with the help of the given options. If the given sentence is correct then select the option 'The given sentence is correct'.The HR will give an topic to test the ability of our employees for the new project will give a topic to testing the ability of The given sentence is correct will gives a topic to test the ability of will give a topic to test the ability of will give a topic to testing the ability of The given sentence is correct will gives a topic to test the ability of will give a topic to test the ability of ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following is the largest windfarm located in India? Muppandal Talcher Vindhayachal Mundra Muppandal Talcher Vindhayachal Mundra ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rank - Windfarm name - Capacity1 - Muppandal windfarm - 1500 MW2 - Jaisalmer Wind Park - 1064 MW3 - Brahmanvel Wind Farm Dhule - 964 MW4 - Damanjodi Wind Farm - 99 MW5 - Tuppadahalli Wind Farm - 56.1 MW
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase 240 V, 1 kW heater is connected across single phase 240 V, 50 Hz supply through an SCR. For firing angle delay of 90˚, calculate the power absorbed in the heater element. 250 W 225 W 275 W 300 W 250 W 225 W 275 W 300 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Resistance of heater, R = V²/PR = 57.6 ohmRMS value of voltage through controlled SCR = (Vm/2π)*(1 + cosα)= 120 VPower absorb by heater = Vrms²/R= 120²/57.6= 250 W
MGVCL Exam Paper (30-07-2021 Shift 2) પાણી : પાણીગ્રહણ :: હસ્ત : ??? પ્રેમાલાપ વિવાહ છુટાછેડા હસ્તમેળાપ પ્રેમાલાપ વિવાહ છુટાછેડા હસ્તમેળાપ ANSWER DOWNLOAD EXAMIANS APP