MGVCL Exam Paper (30-07-2021 Shift 2) Who started the daily newspaper 'National Herald' in 1938? Ram Mohan Roy Jawaharlal Nehru Subhas Chandra Bose Dadabhai Naoroji Ram Mohan Roy Jawaharlal Nehru Subhas Chandra Bose Dadabhai Naoroji ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Fill in the blanks with suitable Article from the given alternatives.I heard ____interesting story yesterday an No article a the an No article a the ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) 1. આપને મુખ્યમત્રીએ ખાસ કામ માટે નિયુક્ત કર્યા છે.2. તેનાથી આંખો ઝીણી કરાઈ3. પ્રધાનમંત્રીએ સ્કુલનું ઉદ્રઘાટન કર્યું.આરોપીએ બધા ગુના કબુલ કરી લીધા.ઉક્ત વાક્યોમાં કેટલા કર્મણી વાક્યો પ્રયોગના છે? કુલ 2 બધા જ કર્તરી વાક્ય પ્રયોગના છે બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે કુલ 1 કુલ 2 બધા જ કર્તરી વાક્ય પ્રયોગના છે બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે કુલ 1 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In a single phase energy meter, the shunt electromagnet is energized by a ____of ____ current coil, thick wire of few turns current coil, thin wire of more turns pressure coil, thin wire of more turns pressure coil, thick wire of few turns current coil, thick wire of few turns current coil, thin wire of more turns pressure coil, thin wire of more turns pressure coil, thick wire of few turns ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In single phase energy meter,Current coil is made up from thick wire having few no. of turns.Pressure coil is made up from thin wire having more no. of turns.
MGVCL Exam Paper (30-07-2021 Shift 2) If all the devices are connected to a central hub, then the topology is called Tree Topology Star Topology Bus Topology Tree Topology Tree Topology Star Topology Bus Topology Tree Topology ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A three-phase, 12 kV, 50 Hz and 300 kW load is operating at 0.8 pf lag. If the pf is to be improved to unity, using star connected capacitor, the per phase value of the reactive VAR required is: 75 kVAR 100 kVAR 50 kVAR 25 kVAR 75 kVAR 100 kVAR 50 kVAR 25 kVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The reactive VAR required = kW*(tanφ1 -tanφ2)Cosφ1 = 0.8φ1 = 36.87 deg.Cosφ2 = 0φ2 = 0 deg.kVAR required = kW*(tan(36.87) - tan(0))= 300*1000(0.75)= 225.00 kVARPer phase value = 225.00/3= 75 kVAR
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