MGVCL Exam Paper (30-07-2021 Shift 2) If all the devices are connected to a central hub, then the topology is called Star Topology Tree Topology Tree Topology Bus Topology Star Topology Tree Topology Tree Topology Bus Topology ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In a test by Murray loop for ground fault on 600 m of cable having a resistance of 1.5 Ω/km, the faulty cable is looped with a sound cable of the same length and area of cross section. If the ratio of the other two arms of the testing network at balance is 3 : 1, find the distance of the fault from the testing end of cables. 300 m 400 m 200 m 100 m 300 m 400 m 200 m 100 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,d is distance in mQ is value of variable resistor in ohmP is variable resistance in ohmHere Q/P = 1/3 is given,d = Q/(P + Q)*Loop length= 1/4*(2*600)= 300 m
MGVCL Exam Paper (30-07-2021 Shift 2) 1. આપને મુખ્યમત્રીએ ખાસ કામ માટે નિયુક્ત કર્યા છે.2. તેનાથી આંખો ઝીણી કરાઈ3. પ્રધાનમંત્રીએ સ્કુલનું ઉદ્રઘાટન કર્યું.આરોપીએ બધા ગુના કબુલ કરી લીધા.ઉક્ત વાક્યોમાં કેટલા કર્મણી વાક્યો પ્રયોગના છે? કુલ 2 કુલ 1 બધા જ કર્તરી વાક્ય પ્રયોગના છે બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે કુલ 2 કુલ 1 બધા જ કર્તરી વાક્ય પ્રયોગના છે બધા જ વાક્યો કર્મણી વાક્ય પ્રયોગના છે ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) The operating time of an inverse definite minimum time (IDMT) overcurrent relay is ____ proportional to the plug-setting multiplier (PSM) and____proportional to the time-multiplier setting (TMS). inversely, directly inversely, inversely directly, directly directly, inversely inversely, directly inversely, inversely directly, directly directly, inversely ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Calculate the inductance per meter of a 50 Ω load cable that has an capacitance of 20 pF/m. 50 nH 25 nH 25 mH 50 mH 50 nH 25 nH 25 mH 50 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Characteristic impedance, Z = √(L/C)50 = √(L/20*10⁻¹²)L = (50*50)*(20*10⁻¹²)L = 50000*10⁻¹²L = 50 nH
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase motor connected to 415 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging. 96.32 µF 66.32 µF 86.32 µF 76.32 µF 96.32 µF 66.32 µF 86.32 µF 76.32 µF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = VIcosφ = 8715 wattQ = VAR required to improve PF = P(tanφ₁ - tanφ₂) = 4670 VARCapacitive Reactance, Xc = V²/Q = 36.8790 ohm.C = (2πfXc)⁻¹ = 86.314 μF
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