MGVCL Exam Paper (30-07-2021 Shift 2) Match the following shown in figure A = (iii) & (2) B = (ii) & (1) A = (i) & (3) C = (ii) & (1) A = (iii) & (2) B = (ii) & (1) A = (i) & (3) C = (ii) & (1) ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) When different types of consumers are charged at different uniform per unit rates, it is called as ____ maximum demand tariff block rate tariff two-part tariff flat rate tariff maximum demand tariff block rate tariff two-part tariff flat rate tariff ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When different types of consumers are charged at different uniform per unit rates, it is said to be Flat Rate Tariff.In this type, the consumers are grouped into different classes.Each class is charged at different uniform rate.
MGVCL Exam Paper (30-07-2021 Shift 2) A generating station having 'n' section busbars each rated at Q kVA with ×% reactance is connected on the tie-bars systems through busbar reactances of b%. Determine the short circuit kVA if a 3-phase fault takes place on one section. Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) + (n-1)/(bn+x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) - (n+1)/(bn-x)] Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) + (n-1)/(bn+x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) - (n+1)/(bn-x)] ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Short circuit kVA of any bus is given by:Skva = Sbase*(100/% X)Where,Sbase - base rating in kVA% X - value of reactance in %
MGVCL Exam Paper (30-07-2021 Shift 2) Fill in the blanks with suitable Article from the given alternatives.I heard ____interesting story yesterday No article an the a No article an the a ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? પરવીન બાબી માધુરી દિક્ષિત કિરણ ખેર અમૃતા સિંહ પરવીન બાબી માધુરી દિક્ષિત કિરણ ખેર અમૃતા સિંહ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circular loop has its radius increasing at a rate of 2 m/s. The loop is placed perpendicular to a constant magnetic field of 0.1 Wb/m². When the radius of the loop is 2 m, the emf induced in the loop will be 0.8π V 0.2π V zero 0.4π V 0.8π V 0.2π V zero 0.4π V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP emf = dΨ/dt = change of flux linkageemf = dф/dtemf = d(B*Area)/dtemf = B*d(area)/dtemf = B*d(πr²)/dtemf = Bπ*2r*dr/dtemf = Bπ*2r*change of radius per unit timeemf = 0.1*π*2*2emf = 4π