MGVCL Exam Paper (30-07-2021 Shift 2) Match the following shown in figure C = (ii) & (1) B = (ii) & (1) A = (i) & (3) A = (iii) & (2) C = (ii) & (1) B = (ii) & (1) A = (i) & (3) A = (iii) & (2) ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A generating station having 'n' section busbars each rated at Q kVA with ×% reactance is connected on the tie-bars systems through busbar reactances of b%. Determine the short circuit kVA if a 3-phase fault takes place on one section. Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) - (n+1)/(bn-x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) + (n-1)/(bn+x)] Q[(1/x) + (n+1)/(bn-x)] Q[(1/x) - (n+1)/(bn-x)] Q[(1/x) + (n+1)/(bn+x)] Q[(1/x) + (n-1)/(bn+x)] ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Short circuit kVA of any bus is given by:Skva = Sbase*(100/% X)Where,Sbase - base rating in kVA% X - value of reactance in %
MGVCL Exam Paper (30-07-2021 Shift 2) In the context of smart meters, the term 'SMETS' stand for Standard Monitoring Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Smart Metering Equipment Technical Specifications Standard Metering Equipment Technical Specifications ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be 9 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s 27 × 10⁸ m/s 9 × 10⁸ m/s 3 × 10⁸ m/s 1 × 10⁸ m/s 27 × 10⁸ m/s ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Speed of EM wave in medium = C/√(εr*μr)= (300000000)/√9= 300000000/3= 100000000= 1*10⁸ m/s
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following is the committee on poverty estimation? Ad hoc committe Karve committee Tendulkar committee S.S.Tarapore committee Ad hoc committe Karve committee Tendulkar committee S.S.Tarapore committee ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A MOSFET rated for 15 A, carries a periodic current as shown in figure. The ON state resistance of the MOSFET is 0.15 Ω. The average ON state loss in the MOSFET is 15 W 33.8 W 7.5 W 3.8 W 15 W 33.8 W 7.5 W 3.8 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ip = 10 ATon = πT = 2πIavg = Ip*√(Ton/T)Iavg = 10*√(1/2)= 7.07 AThe average ON state loss in MOSFET, P = Iavg²*RP = 7.07²*0.15P = 7.5 W
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