MGVCL Exam Paper (30-07-2021 Shift 2)
A circuit breaker is rated 2500 A, 2000 MVA, 33 kV, 3 sec, 3-phase oil circuit breaker. Determine the breaking current.

25 kA
35 kA
2500 A
350 kA

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MGVCL Exam Paper (30-07-2021 Shift 2)
નીચે માંથી ક્યાં રુઢિપ્રયોગનો અર્થ 'છેતરવું' એવો થાય

બે પાંદડે થવું
આડા ઉતરવું
હથેળીમાં ચાંદ દેખાડવો
દસ મારવો

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MGVCL Exam Paper (30-07-2021 Shift 2)
The necessary equation to be solved during the load flow analysis using Fast-Decoupled method is given below:
where B' and B'' are formed using the imaginary part of the bus admittance matrix, Ybus. If the system consists of 6 buses of which one of the bus is slack bus and 2 bues are voltage regulated buses, then then the matrix B' is of order ____and the matrix B'' is of order____, respectivity.
∆P/|Vi| = - B'∆δ
∆Q/|Vi| = - B''∆|V|

6 and 3
3 and 5
5 and 3
3 and 6

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MGVCL Exam Paper (30-07-2021 Shift 2)
Which one of these is not a monitoring and diagnostic test for transformer oil?

Dissolved Gas Analysis
Furanic Compound Analysis
Volatility Level Analysis
Dissolved Metals Analysis

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MGVCL Exam Paper (30-07-2021 Shift 2)
The expression for voltage regulation of a short transmission line for leading power factor is given by: ____, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resitance and 'X' is the line reactance.

(IRcosφ_r + IXsinφ_r)/V_r
(IXcosφ_r + IRsinφ_r)/V_r
(IXcosφ_r - IRsinφ_r)/V_r
(IRcosφ_r - IXsinφ_r)/V_r

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MGVCL Exam Paper (30-07-2021 Shift 2)
In the circuit of figure, the switch is closed to position-1 for a long time. At t = 0 the switch position is changed from postion-1 to postion-2. Find an expression for the current i(t).

i(t) = (E/R) cos√(LC) t A
i(t) = (E/R) sin[1/√(LC)]t A
i(t) = (E/R) sin√(LC) t A
i(t) = (E/R) cos[1/√(LC)]t A

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