Theory of Machine When the sleeve of a Porter governor moves downwards, the governor speed Decreases Remain unaffected First increases and then decreases Increases Decreases Remain unaffected First increases and then decreases Increases ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rigid body, under the action of external forces, can be replaced by two masses placed at a fixed distance apart. The two masses form an equivalent dynamical system, if All of these The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body The center of gravity of the two masses coincides with that of the body The sum of the two masses is equal to the total mass of body All of these The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body The center of gravity of the two masses coincides with that of the body The sum of the two masses is equal to the total mass of body ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In considering friction of a V-thread, the virtual coefficient of friction (μ₁) is given by μ₁ = μ cos β μ₁ = μ/cos β μ₁ = μ/sin β μ₁ = μ sin β μ₁ = μ cos β μ₁ = μ/cos β μ₁ = μ/sin β μ₁ = μ sin β ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A simple spring-mass vibrating system has a natural frequency of fn. If the spring stiffness is halved and the mass is doubled, then the natural frequency will become 8 fn fn/2 4 fn 2 fn 8 fn fn/2 4 fn 2 fn ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a reciprocating steam engine, when the crank has turned from inner dead centre through an angle θ, the angular velocity of the connecting rod is given by ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 2(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h ANSWER DOWNLOAD EXAMIANS APP
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