Theory of Machine When the belt is stationary, it is subjected to some tension known as initial tension. The value of this tension is equal to the Tension in the slack side of the belt Average tension of the tight side and slack side of the belt Tension in the tight side of the belt Sum of the tensions on the tight side and slack side of the belt Tension in the slack side of the belt Average tension of the tight side and slack side of the belt Tension in the tight side of the belt Sum of the tensions on the tight side and slack side of the belt ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine It is required to connect two parallel shafts, the distance between whose axes is small and variable. The shafts are coupled by Oldham's coupling Flexible coupling Knuckle joint Universal joint Oldham's coupling Flexible coupling Knuckle joint Universal joint ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a multiple V-belt drive, if one of the belts is broken, then we should replace The broken belt only None of these All the belts The broken belt and the belts on either side of it The broken belt only None of these All the belts The broken belt and the belts on either side of it ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Sense of tangential acceleration of a link Is opposite to that of velocity Is same as that of velocity Is perpendicular to that of velocity Could be either same or opposite to velocity Is opposite to that of velocity Is same as that of velocity Is perpendicular to that of velocity Could be either same or opposite to velocity ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A torsional system with discs of moment of inertia I₁ and I₂ as shown in the below figure, is gear driven such that the ratio of speed of shaft B to shaft A is 'G'. Neglecting the inertia of gears, the equivalent inertia of disc on shaft B at the speed of shaft A is equal to G².I₂ G.I₂ I₂/G I₂/G² G².I₂ G.I₂ I₂/G I₂/G² ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The relation between number of links (l) and number of joints (j) in a kinematic chain is l = (2/3).(j + 2) l = j + 4 l = (3/4).(j + 3) l = (1/2).(j + 2) l = (2/3).(j + 2) l = j + 4 l = (3/4).(j + 3) l = (1/2).(j + 2) ANSWER DOWNLOAD EXAMIANS APP
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