Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation fails abc None of these Compilation clean but no output xyz Compilation fails abc None of these Compilation clean but no output xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Compilation error. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 Compilation error. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. static native volatile final abstract static native volatile final abstract ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int... args, int y){} void add(Integer... args){} static void add(int args...){} static void add(int[]... args){} static void add(int...args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int args...){} static void add(int[]... args){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword At run-time At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one 20 20 one two one two 20 one one 20 20 one two one two 20 one ANSWER DOWNLOAD EXAMIANS APP
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