Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these Compilation fails abc xyz Compilation clean but no output None of these Compilation fails abc xyz Compilation clean but no output ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} Runtime Exception 0 5 6 Compile with error Runtime Exception 0 5 6 Compile with error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} A block static static A None of these static block A A A block static static A None of these static block A A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} BaseDerived Compilation Error Derived Exception is thrown at runtime BaseDerived Compilation Error Derived Exception is thrown at runtime ANSWER DOWNLOAD EXAMIANS APP
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