Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these abc Compilation clean but no output Compilation fails xyz None of these abc Compilation clean but no output Compilation fails xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 1 and 3 1 and 2 2 and 4 3 and 4 1 and 3 1 and 2 2 and 4 3 and 4 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will compile successfully and display 10 as output. The program will lead to runtime error. None of these The will compile successfully and display 9 as output. The program will lead to compilation error. The program will compile successfully and display 10 as output. The program will lead to runtime error. None of these The will compile successfully and display 9 as output. The program will lead to compilation error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Exception is thrown at runtime BaseDerived Compilation Error Derived Exception is thrown at runtime BaseDerived Compilation Error Derived ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 6 Compile with error 5 Runtime Exception 0 6 Compile with error 5 Runtime Exception ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS