Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these xyz abc Compilation fails Compilation clean but no output None of these xyz abc Compilation fails Compilation clean but no output ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Derived BaseDerived Compilation Error Exception is thrown at runtime Derived BaseDerived Compilation Error Exception is thrown at runtime ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post Compilation fail r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post Compilation fail ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} one two 1 None of these one two 0 Compile time error. one two 10 one two 1 None of these one two 0 Compile time error. one two 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} Compile error at line 1 (static x must be only accessed inside static methods) 44 Compile error at line 3 (static methods can't invoke this) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) 44 Compile error at line 3 (static methods can't invoke this) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int... args, int y){} static void add(int[]... args){} void add(Integer... args){} static void add(int args...){} static void add(int...args){} static void add(int... args, int y){} static void add(int[]... args){} void add(Integer... args){} static void add(int args...){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
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