Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output Compilation fails xyz None of these abc Compilation clean but no output Compilation fails xyz None of these abc ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} None of these A block static static A A static block A None of these A block static static A A static block A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Exception is thrown at runtime Derived BaseDerived Compilation Error Exception is thrown at runtime Derived BaseDerived Compilation Error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. volatile final static abstract native volatile final static abstract native ANSWER DOWNLOAD EXAMIANS APP