Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz Compilation clean but no output None of these abc Compilation fails xyz Compilation clean but no output None of these abc Compilation fails ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} Any class in com.mypackage package. Any class that extends Test. Any class. Only the Test class. None of these Any class in com.mypackage package. Any class that extends Test. Any class. Only the Test class. None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program has a compilation error because we cannot assign radius to radius. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program does not compile because Circle does not have a default constructor. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to runtime error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. The program will lead to compilation error. None of these The program will lead to runtime error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. The program will lead to compilation error. None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. volatile static abstract native final volatile static abstract native final ANSWER DOWNLOAD EXAMIANS APP
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