Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output abc Compilation fails xyz None of these Compilation clean but no output abc Compilation fails xyz None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction? Declare the method with the keyword private. Declare the method with the keyword public and private. Do not declare the method with any accessibility modifiers. Declare the method with the keyword protected. Declare the method with the keyword public. Declare the method with the keyword private. Declare the method with the keyword public and private. Do not declare the method with any accessibility modifiers. Declare the method with the keyword protected. Declare the method with the keyword public. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 Runtime Exception 6 Compile with error 5 0 Runtime Exception 6 Compile with error 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Runtime error It will fail to compile. Compiles and runs with no output. Compiles and runs printing Runtime error It will fail to compile. Compiles and runs with no output. Compiles and runs printing ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. static native volatile abstract final static native volatile abstract final ANSWER DOWNLOAD EXAMIANS APP
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