Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these Compilation clean but no output Compilation fails abc xyz None of these Compilation clean but no output Compilation fails abc xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 2 and 4 3 and 4 1 and 3 1 and 2 2 and 4 3 and 4 1 and 3 1 and 2 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? It will fail to compile. Runtime error Compiles and runs printing Compiles and runs with no output. It will fail to compile. Runtime error Compiles and runs printing Compiles and runs with no output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} one two 0 None of these Compile time error. one two 10 one two 1 one two 0 None of these Compile time error. one two 10 one two 1 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 3 (static methods can't invoke this) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 3 (static methods can't invoke this) ANSWER DOWNLOAD EXAMIANS APP
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