Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz abc None of these Compilation fails Compilation clean but no output xyz abc None of these Compilation fails Compilation clean but no output ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} A block static None of these static A A static block A A block static None of these static A A static block A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A package is a collection of Editing tools Classes and Interfaces Classes Interfaces Editing tools and Interfaces Editing tools Classes and Interfaces Classes Interfaces Editing tools and Interfaces ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. abstract native final volatile static abstract native final volatile static ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int args...){} static void add(int...args){} static void add(int[]... args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int args...){} static void add(int...args){} static void add(int[]... args){} static void add(int... args, int y){} void add(Integer... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The will compile successfully and display 9 as output. None of these The program will compile successfully and display 10 as output. The program will lead to runtime error. The program will lead to compilation error. The will compile successfully and display 9 as output. None of these The program will compile successfully and display 10 as output. The program will lead to runtime error. The program will lead to compilation error. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS