Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these Compilation clean but no output xyz abc Compilation fails None of these Compilation clean but no output xyz abc Compilation fails ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 2 (must access x by writing Tester.x) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 2 (must access x by writing Tester.x) Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to runtime error. The will compile successfully and display 9 as output. None of these The program will compile successfully and display 10 as output. The program will lead to compilation error. The program will lead to runtime error. The will compile successfully and display 9 as output. None of these The program will compile successfully and display 10 as output. The program will lead to compilation error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? It will fail to compile. Compiles and runs printing Runtime error Compiles and runs with no output. It will fail to compile. Compiles and runs printing Runtime error Compiles and runs with no output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword None of these Depends on the code At run-time At Compile-time None of these Depends on the code At run-time At Compile-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 Compilation error. Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 Compilation error. ANSWER DOWNLOAD EXAMIANS APP
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