Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation fails Compilation clean but no output xyz None of these abc Compilation fails Compilation clean but no output xyz None of these abc ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 Runtime Exception 6 Compile with error 5 0 Runtime Exception 6 Compile with error 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} None of these one two 1 one two 0 one two 10 Compile time error. None of these one two 1 one two 0 one two 10 Compile time error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. native static final abstract volatile native static final abstract volatile ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} static void add(int[]... args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int args...){} static void add(int...args){} static void add(int[]... args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int args...){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. None of these The program will lead to runtime error. The program will lead to compilation error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. None of these The program will lead to runtime error. The program will lead to compilation error. ANSWER DOWNLOAD EXAMIANS APP
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