Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output abc Compilation fails None of these xyz Compilation clean but no output abc Compilation fails None of these xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post pre r1 r4 b1 b2 r2 r3 post ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} void add(Integer... args){} static void add(int...args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} void add(Integer... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} 0 None of these Compile with error Runtime Exception 5 0 None of these Compile with error Runtime Exception 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. abstract native final volatile static abstract native final volatile static ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to compilation error. The will compile successfully and display 9 as output. The program will lead to runtime error. The program will compile successfully and display 10 as output. None of these The program will lead to compilation error. The will compile successfully and display 9 as output. The program will lead to runtime error. The program will compile successfully and display 10 as output. None of these ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS