Area Problems What is the diameter of the circle having 3 cm radius? 8 cm 12 cm 1.5 cm 6 cm 8 cm 12 cm 1.5 cm 6 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Radius = Diameter/2 ? Diameter = 2 x Radius = 2 x 3 = 6 cm
Area Problems If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle. 120 140 130 110 120 140 130 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP let length = x and breadth = y then 2(x+y) = 46 => x+y = 23 x²+y² = 17² = 289 now (x+y)² = 23² => x²+y²+2xy= 529 => 289+ 2xy = 529 => xy = 120 area = xy = 120 sq.cm
Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? 13 cm None of these 14cm 12 cm 13 cm None of these 14cm 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems The circumference of a circle is 25 cm. Find the side of the square incribed in the circle. 25/??2 cm 23/??2 29/??3 cm 21/??3 cm 25/??2 cm 23/??2 29/??3 cm 21/??3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm
Area Problems The perimeter of an isosceles triangle is equal to 14 cm . The lateral side is to the base in the ratio 5 : 4 the area of the triangle is? 3/2?21 cm2 2?21 cm2 ?212 1/2?21 cm2 3/2?21 cm2 2?21 cm2 ?212 1/2?21 cm2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let lateral side = (5y) cm and base = (4y) cm ? perimeter = 5y + 5y + 4y = 14 ?y = 1So, the sides are 5 cm , 5 cm and 4 cm Now s= 1/2 (5 + 5 + 4) cm = 7 cm (s-a) = 2 cm (s-b) = 2 cm and (s-c) = 3 cm? Required Area = ? (7 x 2 x 2 x 3) cm2=2?21 cm2
Area Problems The area of rectangle whose length is 5 more than twice its width is 75 sq units. What is the perimeter of the rectangle? 24 unit 40 unit 30 unit 20 unit 24 unit 40 unit 30 unit 20 unit ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the width of the rectangle = k units? Length = (2k + 5) units.According to the question,Area = k(2k + 5)? 75 = 2k2 + 5k? 2k2 + 5k - 75 = 0 ? 2k2 + 15k - 10k - 75 = 0 ? k(2k + 15) - 5(2k + 15) = 0 ? (2k + 15) (k - 5) = 0 ? k = 5 and -15/2Width cannot be negative. ? Width = 5 units? Length = 2x + 5 = 2 x 5 + 5 = 15 unit? perimeter of the rectangle = 2(15 + 5) = 40 units
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