Area Problems Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm. 84 22 64 44 84 22 64 44 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let a = 13, b = 14 and c = 15. Then, s = 1 2 a + b + c =21 (s- a) = 8, (s - b) = 7 and (s - c) = 6. Area = s s - a s - b s - c = 21 × 8 × 7 × 6 = 84 sq.cm
Area Problems The diagonals of two squares are in the ratio of 3 : 2. Find the ratio of their areas. 9 : 5 9 : 4 9 : 2 9 : 7 9 : 5 9 : 4 9 : 2 9 : 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the diagonals of the squares be 3x and 2x.? Ratio of their areas = [(1/2) (3x2)] / [(1/2) (2x2)] = 9/4
Area Problems If the circumference of a circle is the 352 meters, then its area in m square is? 6589 8956 5986 9856 6589 8956 5986 9856 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP circumference = 2?r = 2 x (22 / 7) x r = 352? r = (352 x 7) / (22 x 2) =56 cmNow area = ?r2 = (22 / 7) x 56 x 56 m2= 9856 m2
Area Problems The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ? Question : What is the height of a right-angled triangle ? Statements : A. The area of the triangle is 20 times its base. B. The perimeter of the triangle is equal to that of a square of the side 10 cm. Both A & B are required Only statement B is required Only statement A is required Neither (A) nor (B) is reuired Both A & B are required Only statement B is required Only statement A is required Neither (A) nor (B) is reuired ANSWER EXPLANATION DOWNLOAD EXAMIANS APP From statement (A), 20b = (1/2) × b × h h = 40 cm.
Area Problems One side of a parallelogram is 14 cm. Its distance from the opposite side is 16 cm. The area of the parallelogram is? 56? sq. cm 112 sq. cm 210 sq. cm 224 sq. cm 56? sq. cm 112 sq. cm 210 sq. cm 224 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Side of parallelogram x distance from the opposite side= 14 x 16 cm2= 224 cm2
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 88 40 34 68 88 40 34 68 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
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