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Area Problems

Area Problems
The area of an equilateral triangle whose side is 8 cms is?

4?3 cm2
16?3 cm2
64 cm2
21.3 cm2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Req. Area = ?3/4 x a2 = ?3/4 x 82 cm2= 16?3 cm2

Area Problems
The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm. find its height.

36/7 cm
46/7 cm
56/7 cm
26/7 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, area = 40 sq cm, base = 28 cm and height = perpendicular = ?Area = (base x perpendicular) / 2 ? 40 = (28 x perpendicular) / 2 ? perpendicular = 40/14 = 20/7 = 26/7 cm

Area Problems
The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field?

(4 x 104) sq m
(4 x 10) sq m
(4 x 103) sq m
(4 x 102) sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m

Area Problems
If the length of diagonal AC of a square ABCD is 5.2 cm then area of the square ABCD is?

10 sq.cm
15.12 sq.cm
12.62 sq.cm
13.52 sq.cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1/2 x (Diagonal)2= (1/2) x 5.2 x 5.2 cm2= 13.52 cm2

Area Problems
Find the area of a triangle whose sides measure 8 cm, 10 cm and 12 cm.

7?93 sq cm
5?63 sq cm
6?53 sq cm
8?63 sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, a = 8 cm, b = 10 cm and c = 12 cm We know, that s = (a + b + c)/2 = (8 + 10 + 12)/2= 30/2 = 15 cm ? (s - a) = (15 - 8) = 7 cm (s - b) = (15 - 10) = 5 cm (s - c) = (15 - 12) = 3 cm ? Area = ?s(s - a) (s - b) (s - c)= ?15 x 7 x 5 x 3= ?1575= ?25 x 63= 5?63 cm

Area Problems
The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is?

4 meters
3 meters
None of these
15 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m

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