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Area Problems

Area Problems
Find the area of a rectangle having 15m length and 8m breadth.

111 sq m
120 sq m
115 sq m
125 sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = Length x Breadth= 15 x 8 = 120 sq m

Area Problems
The length of a rectangular field is increased by 60 % . By what percent would the width have to be decreased to maintain the same area?

371/2%
75%
60%
120%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = L and breadth = BLet , New breadth = ZThen, New length = ( 160 / 100) L.= 8L / 5? 8L / 5 x Z = LBor Z = 5B/8Decrease in breadth = (B-5B/8)= 3B/8? Decrease in percent = (3B/8 x1/B ) x 100 %= 371/2%

Area Problems
A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

rs.258
rs.358
rs.158
rs.58

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x  (75/100) = Rs. 258

Area Problems
The radius of a circle is so increased that its circumference increased by 5%. The area of the circle, then increases by

11.25%
10.25%
12.5%
10.5 %

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Increase in circumference of circle = 5%? Increase in radius is also 5%.Now, increase in area of circle = 2a + (a2/100) %Where, a = increase in radius= 2 x 5 + (5 x 5)/100 % = 10.25%

Area Problems
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

88
68
34
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft

Area Problems
A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

Rs. 258
Rs. 458
Rs. 358
Rs. 558

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to be plastered =  2 l + b × h + l × b   = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m   Cost of plastering =  744 × 75 100 = R s . 558

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