Area Problems Find the area of a rectangle having 15m length and 8m breadth. 111 sq m 120 sq m 115 sq m 125 sq m 111 sq m 120 sq m 115 sq m 125 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by? 62% None of these 82% 42% 62% None of these 82% 42% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%
Area Problems The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is 154 49 378 1078 154 49 378 1078 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2
Area Problems A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Rs. 258 Rs. 558 Rs. 358 Rs. 458 Rs. 258 Rs. 558 Rs. 358 Rs. 458 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = 2 l + b × h + l × b = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m Cost of plastering = 744 × 75 100 = R s . 558
Area Problems The diameter of a circle is 105 cm less than the circumference. What is the diameter of the circle? 49 cm 48 cm 46 cm 44 cm 49 cm 48 cm 46 cm 44 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ?d-d = 105 cm ? (? -1 ) d = 105 cm? [(22/7)-1] x d = 105 cm? d = (7/15) x 105 cm = 49 cm
Area Problems An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: 4% 2.02% 2% 4.04% 4% 2.02% 2% 4.04% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%
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