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Area Problems

Area Problems
Find the area of a rectangle having 15m length and 8m breadth.

125 sq m
120 sq m
115 sq m
111 sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = Length x Breadth= 15 x 8 = 120 sq m

Area Problems
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

88
68
34
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft

Area Problems
If the area of a semi-circle be 77 sq m, find its perimeter.

54 m
42 m
36 m
48 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question, Area of semi- circle = 77 m(1/2) x ? x r2 = 77? r2 = (77 x 2 x 7)/22? r = 7m ?Circumference of semi- circle =?r + 2r= ( ? + 2)r = [(22/7) + 2] x 7 = 36 m

Area Problems
The ratio of the area of two square, one having and double its diagonal than the other is?

4:1
2:1
3:1
3:2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the diagonal of one square be (2d) cmThen, diagonal of another square = d cm? Area of first square = [ 1/2 x (2d)2] cm2Area of second square = (1/2 x d2) cm2? Ratio of area = (2d)2/ d2= 4/1 = 4: 1

Area Problems
If area of a square is 64 sq cm, then find the area of the circle formed by the same perimeter.

256/? sq cm
318/? sq cm
215/? sq cm
216/? sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square = 64 sq cm (Side)2 = 64 ? Side = ?64 = 8 cmAccording to the question,? 2?r = 4 x 8 ? r = (4 x 8)/2?? r = 16/?? Area of the circle = ? x (16/?) x (16/?) sq cm = 256/? sq cm.

Area Problems
The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by?

82%
42%
62%
None of these

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%

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