Area Problems If 88 m wire is required to fence a circular plot of land, then the area of the plot is? 616 m2 526 m2 None of these 556 m2 616 m2 526 m2 None of these 556 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of circular plot= 88 m? 2 x (22/7) x r = 88? r = 88 x (7/22) x (1/2) = 14 m Now area = ?r2=( 22/7) x 14 x 14 m2= 616 m2
Area Problems If the diagonal of a square is double, how does the area of the square change? Becomes four fold Becomes two fold Becomes three fold None of these Becomes four fold Becomes two fold Becomes three fold None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas = area of original square / area of new square = [ d2 / 2 ] / [ (2d)2 / 2 ] = 1/4? New area becomes 4 fold.
Area Problems The ratio of the area of a square to that of the square drawn on its diagonal is 2;3 3:1 4:1 1:2 2;3 3:1 4:1 1:2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP atio = a 2 2 a 2
Area Problems Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is 36° 40° 18° 54° 36° 40° 18° 54° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let First angle = 3kSecond angle = 4kThird angle = 5k and Fourth angle = 8kWe know 3k + 4k + 5k + 8k = 360°? 20k = 360° ? k = 18 °Measure of smallest angle = 3k =3 x 18 ° = 54 °
Area Problems The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is? 6 sq. meters . 12 sq. meters . 18 sq. meters . 9 sq. meters . 6 sq. meters . 12 sq. meters . 18 sq. meters . 9 sq. meters . ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2
Area Problems If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals. 9% 5% 6% 4% 9% 5% 6% 4% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,Percentage increase in diagonals = 5%
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