Area Problems The area of a circle of radius 5 is numerically what percent its circumference? 450% 350% 150% 250% 450% 350% 150% 250% ANSWER DOWNLOAD EXAMIANS APP
Area Problems The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is? 36 cm 20 cm 24 cm 30 cm 36 cm 20 cm 24 cm 30 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm
Area Problems The inner circumference of a circular race track, 14 m wide is 440 m . Then the radius of the outer circle is? 77 m 70 m 84 m 56 m 77 m 70 m 84 m 56 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of a circular = 2?r? 2 x (22 / 7) x r = 440? r = [440 x (7/22) x (1/2)] = 70 m? Radius of outer circle = (70 + 14) m = 84 m
Area Problems The diagonal of a rectangle is √41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be: 18 cm 9 cm 41 cm 20 cm 18 cm 9 cm 41 cm 20 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √l2 + b2 = √41. Also, lb = 20. (l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81 ⟹ (l + b) = 9. ∴ Perimeter = 2(l + b) = 18 cm
Area Problems A rectangle has 15 cm as its length and 150 cm 2 as its area .Its area is increased to 1 1 / 3 times the original area by increasing only its length . Its new perimeter is? 60 cm 50 cm 70 cm 80 cm 60 cm 50 cm 70 cm 80 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Breadth of the rectangle = (150/15) cm= 10 cmNew area = (4/3 x 150) cm2= 200 cm2New length = 200/10 cm=20 cmNew perimeters = 2(20 + 10) cm= 60 cm
Area Problems The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height? 16 cm 14 cm 13 cm 12 cm 16 cm 14 cm 13 cm 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let height =x Then, base =2x 2x * x = 338 =>x=13
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