• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

Area Problems

Area Problems
The area of a circle of radius 5 is numerically what percent its circumference?

250%
150%
350%
450%

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
The diagonal of the floor of a rectangular closet is 7½ feet. The shorter side of the closet is 4½ feet. What is the area of the closet in square feet?

27
37
5(1/4)
13(1/2)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other side = (15 / 2) 2 - (9 / 2) 2 ft = (225 / 4) - (81 / 4) ft = 144 / 4 ft = 6 ft Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

Area Problems
A veranda 40 meters long 15 meters broad is to paved with stones each measuring 6 dm by 5 dm. the number of stones required is?

2000
3000
None of these
1000

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length = (40 x 10 ) dm = 400 dm.Breadth = (15 x 10 ) dm = 150 dm.Area of veranda = (400 x 150 ) dm2Area of one stone = (6 x 5 ) dm2? Required number of stones = (400 x 150) /(6 x 5) = 2000

Area Problems
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

2520 m2
2420 m2
2480 m2
1520 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. ∴ Area = (l x b) = (63 x 40) m2 = 2520 m2

Area Problems
Find the area of a triangle whose sides measure 8 cm, 10 cm and 12 cm.

5?63 sq cm
8?63 sq cm
7?93 sq cm
6?53 sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, a = 8 cm, b = 10 cm and c = 12 cm We know, that s = (a + b + c)/2 = (8 + 10 + 12)/2= 30/2 = 15 cm ? (s - a) = (15 - 8) = 7 cm (s - b) = (15 - 10) = 5 cm (s - c) = (15 - 12) = 3 cm ? Area = ?s(s - a) (s - b) (s - c)= ?15 x 7 x 5 x 3= ?1575= ?25 x 63= 5?63 cm

Area Problems
The length of a rectangular field is increased by 60 % . By what percent would the width have to be decreased to maintain the same area?

120%
371/2%
75%
60%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = L and breadth = BLet , New breadth = ZThen, New length = ( 160 / 100) L.= 8L / 5? 8L / 5 x Z = LBor Z = 5B/8Decrease in breadth = (B-5B/8)= 3B/8? Decrease in percent = (3B/8 x1/B ) x 100 %= 371/2%

MORE MCQ ON Area Problems

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑