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Area Problems

Area Problems
The area of a circle of radius 5 is numerically what percent its circumference?

450%
250%
350%
150%

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
A rectangle has 20 cm as its length and 200 sq cm as its area. If the area is increased by 1 1/ 5 time the original area by increase its length only then the perimeter of the rectangle so formed (in cm) is

68
72
64
60

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

l1 = 20 cm, A1 = 200 sq cm? b1 = 200/20 = 10 cmNow, A2 = 200 x 6/5 = 240 sq cm b2 = 10 cm? l2 = 240/10 = 24 cm? Perimeter of new rectangle = 2(l2 + b2)= 2(24 + 10) = 2 x 34 = 68 cm

Area Problems
The diagonal of a rectangle is √41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

41 cm
9 cm
18 cm
20 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

√l2 + b2 = √41. Also, lb = 20. (l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81 ⟹ (l + b) = 9. ∴ Perimeter = 2(l + b) = 18 cm

Area Problems
The breadth of a rectangle is 25 m. The total cost of putting a grass bed on this field was ? 12375, at the rate of ? 15 per sq m. What is the length of the rectangular field?

33 m
32 m
27 m
30 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to the rectangular field = 12375/15 = 825 sq mAccording to the question, (L x B) = 825 [L = length and B = breadth]? L x 25 = 825 ? L = 825/25 = 33 m

Area Problems
The three sides of a triangle are 15, 25 and x units. Which one of the following is correct?

10
10? x ? 40
10 ? x
10

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In a triangleSum of two sides is always greater than 3rd side i.e., x < 25 + 15 = 40 .....(i)Difference of two sides is always less than 3rd side i.e., 25 - 15 = 10 < x ...(ii) From Eqs. (i) and (ii) , we get 10 < x < 40

Area Problems
A circular disc of area 0.49 ? square meters, rolls down a length of 1.76 km. The number of revolutions it makes is?

600
300
400
4000

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = ?r2 = 0.49? ? r = 0.7 mNumber of revolutions = total distance / circumference = (1.76 x 1000) / (2 x 22/7 x 0.7) = 400

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