Area Problems The area of a circle of radius 5 is numerically what percent its circumference? 450% 350% 150% 250% 450% 350% 150% 250% ANSWER DOWNLOAD EXAMIANS APP
Area Problems The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ? Question : What is the height of a right-angled triangle ? Statements : A. The area of the triangle is 20 times its base. B. The perimeter of the triangle is equal to that of a square of the side 10 cm. Neither (A) nor (B) is reuired Only statement B is required Both A & B are required Only statement A is required Neither (A) nor (B) is reuired Only statement B is required Both A & B are required Only statement A is required ANSWER EXPLANATION DOWNLOAD EXAMIANS APP From statement (A), 20b = (1/2) × b × h h = 40 cm.
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? None of these 3 meters 4 meters 15 meters None of these 3 meters 4 meters 15 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems The ratio of the corresponding sides of two similar triangles is 3 : 4, The ratio of their areas is? ? 3: 2 4 : 3 9 : 16 3 : 4 ? 3: 2 4 : 3 9 : 16 3 : 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of similar triangle = Ratio of the square of corresponding sides = (3x)2 / (4x)2 = 9x2 / 16x2 = 9/16 = 9 : 16
Area Problems A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is? Rs. 500 Rs. 700 Rs. 800 Rs. 600 Rs. 500 Rs. 700 Rs. 800 Rs. 600 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of verandah = [(25 x 20) -(20 x 15)] m2= 200 m2? Cost of flooring = Rs. (200 x 3.50)= Rs. 700
Area Problems The cross section of a canal is a trapezium in shape . If the canal is a trapezium in shape. If the canal is 10 meters wide at the top and 6 meters wide at bottom and the area of cross section is 640 sq. meters The depth of canal is? 80 meters 160 meters 40 meters 384 meters 80 meters 160 meters 40 meters 384 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Cross section area = 1/2 x ( a + b ) x d where a and b are the parallel sides, d is the perpendicular distance between them.? 1/2 x ( a + b ) x d = 640? d = (640 x 2) / 16 = 80m
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