Area Problems One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram? 22.56 cm2 12.56 cm2 14.56 cm2 16.76 cm2 22.56 cm2 12.56 cm2 14.56 cm2 16.76 cm2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Base x Height = 8.06 x 2.08 = 16.76 cm2
Area Problems The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side. 9 cm ?3 cm 3?3 cm 3 cm 9 cm ?3 cm 3?3 cm 3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm
Area Problems The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle? 18 cm None of these Data inadequate 24 cm 18 cm None of these Data inadequate 24 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2(l + b) = 5 b 1 ⟹ 2l + 2b = 5b ⟹ 3b = 2l b = 2 l 3 Then, Area = 216 cm2 ⟹ l x b = 216 ⟹l x 2 l = 216 3 ⟹ l2 = 324 ⟹ l = 18 cm
Area Problems The area of a circle of radius 5 is numerically what percent its circumference? 150% 450% 350% 250% 150% 450% 350% 250% ANSWER DOWNLOAD EXAMIANS APP
Area Problems The Number of rounds that a wheel of diameter 7/11 m will make in going 4 km, is? 1500 2000 1000 1700 1500 2000 1000 1700 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Number of round = total distance / circumference of wheel.= (4 x 1000) / ?d= (4 x 1000) / ( 22/7 x 7/11) = 2000
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 40 88 34 68 40 88 34 68 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
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