Area Problems The length and breadth of a playground are 36 m and 21 m respectively. Flagstaffs are required to be fixed on all along the boundary at a distance of 3 m apart. The number of flagstaffs will be? 40 38 37 39 40 38 37 39 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Perimeter = 2 x (36 + 21 ) m = 144 m ? Number of flagstaffs = 144 / 3 = 38
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.258 rs.358 rs.58 rs.158 rs.258 rs.358 rs.58 rs.158 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
Area Problems One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram? 22.56 cm2 16.76 cm2 12.56 cm2 14.56 cm2 22.56 cm2 16.76 cm2 12.56 cm2 14.56 cm2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Base x Height = 8.06 x 2.08 = 16.76 cm2
Area Problems A circle and a square have same area. The ratio of the side of the square and the radius of the circle is? ? : 1 1 : ? 1 : ?? ?? : 1 ? : 1 1 : ? 1 : ?? ?? : 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? Area of square = Area of circle ? x2 = ?r2? x/r = ?? = ? ? : 1
Area Problems An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: 4.04% 2.02% 4% 2% 4.04% 2.02% 4% 2% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%
Area Problems Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm. 15 cm 20 cm 18 cm 14 cm 15 cm 20 cm 18 cm 14 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm
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