Area Problems The length and perimeter of a rectangle are the ratio of 5 : 18 What well be the ratio of its length and breadth? 3 : 5 5 : 4 4 : 7 4 : 3 3 : 5 5 : 4 4 : 7 4 : 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,l/[2(l + b)] = 5/18? 10l + 10b = 18l = 10b? l/b = 10/8 = 5/4? l : b = 5 : 4Hence, ratio of length and breadth of a rectangle is 5 : 4
Area Problems The altitude of an equilateral triangle of side 2 ? 3 cm is? ? 3/2 cm 1/2 cm ? 3/4 3 cm ? 3/2 cm 1/2 cm ? 3/4 3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.58 rs.158 rs.258 rs.358 rs.58 rs.158 rs.258 rs.358 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
Area Problems If the radius of a circle is increased by 6%, find the percentage increase in its area. 8.39% 17% 12.36% 15% 8.39% 17% 12.36% 15% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 According to the formula,Percentage increase in area= 2a + [a2/100]%= 2 x 6 + [36/100]%= (12 + 0.36)%= 12.36%
Area Problems One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is? 4?5 m2 20 m 2 15 m2 12 m2 4?5 m2 20 m 2 15 m2 12 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 88 40 68 34 88 40 68 34 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
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