Area Problems The area of a circular field is 13.86 hectares . The cost of fencing it at the rate of 20 paisa per meter is? Rs. 277.20 Rs. 198 Rs. 264 Rs. 324 Rs. 277.20 Rs. 198 Rs. 264 Rs. 324 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 22/7 x r2 = 13.86 x 10000? r2 = (13.86 x 10000 x 7) / 22? r = 210 m ? Circumference = [2 x (22/7) x 210 ] m = 1320 m Cost of fencing = Rs. (1320 x 20)/100= Rs . 264
Area Problems The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height? 12 cm 13 cm 14 cm 16 cm 12 cm 13 cm 14 cm 16 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let height =x Then, base =2x 2x * x = 338 =>x=13
Area Problems The length of minute hand of a wall clock is 7 cms. The area swept by minute hand in 30 minutes is? 77 sq. cm 210 sq. cm 154 sq. cm 147 sq. cm 77 sq. cm 210 sq. cm 154 sq. cm 147 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Angle swept in 30 min= 180° Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2 = 77 cm2
Area Problems The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side. 3 cm 9 cm ?3 cm 3?3 cm 3 cm 9 cm ?3 cm 3?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 40 88 68 34 40 88 68 34 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
Area Problems The altitude of an equilateral triangle of side 2 ? 3 cm is? ? 3/2 cm ? 3/4 1/2 cm 3 cm ? 3/2 cm ? 3/4 1/2 cm 3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.
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