Let the radius of circle is 'r' and a side of a square is 'a', then given condition2?r = 4a ? a = ?r/2? Area of square = (?r/2)2 = ?2 /4r2 = 9.86r2/4 = 2.46r2and area of circle = ?r2 = 3.14;r2and let the side of equilateral triangle is x.Then, given condition,3x = 2?r ? x = 2?r/3? Area of equilateral triangle = ?3/4 x 2= ?3/4 x 4?2r2/9= ?2/3?3r2= 1.89r2Hence, Area of circle > Area of square > Area of equilateral triangle.
EXAMIANS