Area Problems One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is? 20 m 2 12 m2 4?5 m2 15 m2 20 m 2 12 m2 4?5 m2 15 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2
Area Problems A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be 5544 7744 8844 4444 5544 7744 8844 4444 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP length of wire = 2 ?r = 2 x (22/7 ) x 56 = 352 cmside of the square = 352/4 = 88cmarea of the square = 88 x 88 = 7744sq cm
Area Problems If the ratio of the area of two square is 9 : 1 the ratio of their perimeters is? 3:4 9:1 3:1 1:3 3:4 9:1 3:1 1:3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the area of square be (9x)2 m2 and (x2) m2Then, their sides are (3x) m and x metres respectively? Ratio of their perimeters = 12x / 4x=3:1
Area Problems Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm. 18 cm 14 cm 15 cm 20 cm 18 cm 14 cm 15 cm 20 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm
Area Problems The circumference of a circle is 25 cm. Find the side of the square incribed in the circle. 21/??3 cm 25/??2 cm 29/??3 cm 23/??2 21/??3 cm 25/??2 cm 29/??3 cm 23/??2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm
Area Problems The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is? 12 sq. meters . 9 sq. meters . 18 sq. meters . 6 sq. meters . 12 sq. meters . 9 sq. meters . 18 sq. meters . 6 sq. meters . ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2
EXAMIANS