Area Problems The circumference of a circle is 25 cm. Find the side of the square incribed in the circle. 21/??3 cm 23/??2 25/??2 cm 29/??3 cm 21/??3 cm 23/??2 25/??2 cm 29/??3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm
Area Problems A railing of 288 m is required for fencing a semi-circular park. Find the area of the park. (? = 22/7) 8956 m2 9865 m2 4928 m2 9856 m2 8956 m2 9865 m2 4928 m2 9856 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the radius of the park be r, then?r + 2r = 288(? + 2)r = 288? [(22/7) + 2]r = 288? r = (288 x 7)/36 = 56 ? Area of the park = (1/2)?r2= (1/2) x (22/7) x 56 x 56= 4928
Area Problems Square units 13 by 9 of an office area is 127 107 117 97 127 107 117 97 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
Area Problems The area of a rectangle, 144 m long is the same as that of a square having a side 84 m long. The width of the rectangle is? 14 m Cannot be determined 49 m 7 m 14 m Cannot be determined 49 m 7 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the square = (84 + 84) m2Area of the rectangle = (144 x width) m2From question both area would be same,? Width = (84 x 84) / 144 m = 49 m
Area Problems The length of a rectangular plot is twice of its width. If the length of a diagonal is 9?5 meters, the perimeter of the rectangular is? None of these 81 m 54 m 27 m None of these 81 m 54 m 27 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = y meters,Then, length = 2y meters? Diagonal = ?y2 + (2y)2 = ?5y2 metersSo, ?5y2 = 9 ?5? y= 9Thus, breadth = 9 m and length = 18 m? Perimeter = 2 (18 + 9) m = 54m.
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.58 rs.258 rs.358 rs.158 rs.58 rs.258 rs.358 rs.158 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
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