Area Problems The circumference of a circle is 25 cm. Find the side of the square incribed in the circle. 25/??2 cm 23/??2 21/??3 cm 29/??3 cm 25/??2 cm 23/??2 21/??3 cm 29/??3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 4 meters None of these 15 meters 3 meters 4 meters None of these 15 meters 3 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 40 34 88 68 40 34 88 68 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
Area Problems Area of a four wall of a room is 77 square meters . the length and breadth of room are 7.5 meters and 3.5 meters respectively . the height of the room is? 7.7 meters 5.4 meters 6.77 meters 3.5 meters 7.7 meters 5.4 meters 6.77 meters 3.5 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of four walls = 2 x (l + b ) x h? 2 x (7.5 + 3.5 ) x h = 77 m2? h = 77 / (2 x 11) = 7/2? h = 3.5 meters
Area Problems The length of a rectangle room is 4 meters . if it can be partitioned into two equal square rooms . what is the length of each partition in meters? 1 4 2 Data inadequate 1 4 2 Data inadequate ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the width of the room be x membersThen, its area = (4x) m2Area of each new square room = (2x)m2Let the side of each new room = y metersThen, y2 = 2xClearly, 2x is a complete square when x=2? y2 = 4? y = 2 m .
Area Problems The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base. 3 cm 2 cm 4 cm 1 cm 3 cm 2 cm 4 cm 1 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm
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