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Area Problems

Area Problems
The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side.

?3 cm
3 cm
3?3 cm
9 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm

Area Problems
A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece?

3.5 cm
28 cm
14 cm
7 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Circular piece is 4 x 11 = 44 cm long, Then Circumference of circle is given by, 44 = pi x D, where D is the diameter D = 44 / pi Take pi = 22 / 7, then D = 44 / (22/7) = (44 x 7) / 22 D = 14 cm.

Area Problems
One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is?

12 m2
15 m2
20 m 2
4?5 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2

Area Problems
The ratios of areas of two squares, one having its diagonal double than the other is

3:1
2:1
2:3
4:1

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is?

Rs. 1800
Rs. 810
Rs. 900
Rs. 360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900

Area Problems
If the sides of a squares is increased by 25%, then the area of the squares will be increased by

50%
53.75%
56.25%
125%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%

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