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Area Problems

Area Problems
The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side.

9 cm
3?3 cm
3 cm
?3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm

Area Problems
The area of a rectangle, 144 m long is the same as that of a square having a side 84 m long. The width of the rectangle is?

7 m
14 m
49 m
Cannot be determined

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of the square = (84 + 84) m2Area of the rectangle = (144 x width) m2From question both area would be same,? Width = (84 x 84) / 144 m = 49 m

Area Problems
If the radius of a circle be reduced by 50%. Its area is reduced by?

34.5%
65.5%
39.5%
31.5%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Original area = ? x (r/2)2 = ?r2/4Reduction in area = ? r2 - 3? r2/4? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %= 75%

Area Problems
A rectangle has 15 cm as its length and 150 cm 2 as its area .Its area is increased to 1 1 / 3 times the original area by increasing only its length . Its new perimeter is?

50 cm
60 cm
80 cm
70 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Breadth of the rectangle = (150/15) cm= 10 cmNew area = (4/3 x 150) cm2= 200 cm2New length = 200/10 cm=20 cmNew perimeters = 2(20 + 10) cm= 60 cm

Area Problems
A cost of cultivating a square field at a rate of ? 135 per hectare is ? 1215. The cost of putting a fence around it at the rate of 75 paise per meter wouldbe

? 360
? 900
? 1800
? 810

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of the field =1215/135 = 9 hec= 90000 m2 [1 hec =10000 m2]? Side of the field = ?90000 = 300 mPerimeter of the field = 4 x 300 = 1200 mNow, cost of putting a fence around field = (1200 x 75)/100 = ? 900

Area Problems
The radius of a circle has been reduced from 9 cm to 7 cm . the appropriate percentage decrease in area is?

65.5 %
39.5 %
31.5 %
34.5 %

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Original area = (22/7) x 9 x 9 cm2New area = (22/7) x 7 x 7 cm2? Decrease = 22/7 x [(9)2 -(7)2] cm2=(22/7) x 16 x 2 cm2Decrease percent = [(22/7 x 16 x 2) /( 7/22 x 9 x 9)] x 100 %= 39.5 %

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