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Area Problems

Area Problems
The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side.

?3 cm
3?3 cm
3 cm
9 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm

Area Problems
If the side of a square is increased by 25%, then how much percent does its area get increased?

125
56.25
156.25
50

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let area 100 m2Then, side = 10 m New side = 125 % of 10= (125/100) x 10= 12.5 m New area = 12.5 x 12.5 m2=(12.5)2 sq. m? Increase in area = (12.5)2 - (10)2 m2= 22.5 x 2.5 m2=56.25 m2% Increase = 56.25 %

Area Problems
The ratio of the radii of two circle is 1:3 the radio of their areas is?

1:6
1:3
None of these
1:9

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Radio of areas = area of first circle : area of 2nd circle= ?r2 / ?(3r)2= ?r2/ 9 ?r2= 1/9 = 1: 9

Area Problems
The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by?

42%
82%
None of these
62%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%

Area Problems
One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram?

12.56 cm2
22.56 cm2
16.76 cm2
14.56 cm2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of parallelogram = Base x Height = 8.06 x 2.08 = 16.76 cm2

Area Problems
A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is?

Rs. 600
Rs. 800
Rs. 700
Rs. 500

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of verandah = [(25 x 20) -(20 x 15)] m2= 200 m2? Cost of flooring = Rs. (200 x 3.50)= Rs. 700

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