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Area Problems

Area Problems
The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side.

?3 cm
9 cm
3 cm
3?3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm

Area Problems
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

1520 m2
2420 m2
2480 m2
2520 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. ∴ Area = (l x b) = (63 x 40) m2 = 2520 m2

Area Problems
The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?

20 cm
24 cm
30 cm
36 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm

Area Problems
The wheel of an engine turns 350 times round its axle to cover a distance of 1.76 km. The diameter of the wheel is

9 cm
?3 cm
3?3 cm
3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Distance covered in 1 round = (Total Distance) / (Total round)= (1.76 x 1000)/350= 176/35 m ? 2?r = (1.76 x 100) / 35 cm2? = Diameter = 17600 x 7/22 x 35 = 160 cm

Area Problems
If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

120
130
110
140

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

let length = x and breadth = y then 2(x+y) = 46 => x+y = 23 x²+y² = 17² = 289 now (x+y)² = 23² => x²+y²+2xy= 529 => 289+ 2xy = 529 => xy = 120 area = xy = 120 sq.cm

Area Problems
The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is?

none of these
260 m
360 m
280 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m

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