• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

Area Problems

Area Problems
Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is

0.75 m2
1.5 m2
1.5 m2
0.375 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of rhombus =(d1 x d2)/2 =(1 x 1.5)/2 m2= 0.75 m2

Area Problems
If area of a square is 64 sq cm, then find the area of the circle formed by the same perimeter.

256/? sq cm
318/? sq cm
216/? sq cm
215/? sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square = 64 sq cm (Side)2 = 64 ? Side = ?64 = 8 cmAccording to the question,? 2?r = 4 x 8 ? r = (4 x 8)/2?? r = 16/?? Area of the circle = ? x (16/?) x (16/?) sq cm = 256/? sq cm.

Area Problems
The diameter of a circle is 105 cm less than the circumference. What is the diameter of the circle?

48 cm
46 cm
44 cm
49 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? ?d-d = 105 cm ? (? -1 ) d = 105 cm? [(22/7)-1] x d = 105 cm? d = (7/15) x 105 cm = 49 cm

Area Problems
The length and breadth of a playground are 36 m and 21 m respectively. Flagstaffs are required to be fixed on all along the boundary at a distance of 3 m apart. The number of flagstaffs will be?

39
38
40
37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Perimeter = 2 x (36 + 21 ) m = 144 m ? Number of flagstaffs = 144 / 3 = 38

Area Problems
If the circumference of a circle is increased by 50%, then its area will be increased by?

100%
125%
225%
50%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Original circumference = 2?r New circumference = (150 /100) x 2 ?r = 3?r 2?R = 3?r? R = 3r/2 Original area = ?r2New area = ?R2= ?9r2 / 4 = 9?r2/4Increase in area = (9?r2/4 ) - (?r2)= (5/4) ?r2Req. increase per cent = [{(5/4) ?r2} / {?r2}] x 100 = 125 %

Area Problems
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

88
40
34
68

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft

MORE MCQ ON Area Problems

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑