Area Problems A park of 10 meters long and 8 meters broad. What is the length of the longest pole that can be placed in the park? 13.4 metres 10 metres 12.8 metres 18 metres 13.4 metres 10 metres 12.8 metres 18 metres ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of the longest pole = ? [(10)2 + (8)2] m = ? 164 m = 12.8 m
Area Problems The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is? 260 m 360 m none of these 280 m 260 m 360 m none of these 280 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m
Area Problems In a rhombus, whose area is 144 sq.cmone of its diagonal is twice as long as the other, The lengths of its diagonals are? 6 cm, 12 cm 24 cm, 48 cm 12 cm, 24 cm 6 ?2 cm, 12?2 cm 6 cm, 12 cm 24 cm, 48 cm 12 cm, 24 cm 6 ?2 cm, 12?2 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus = (d1 x d2) / 2? (d x 2d ) / 2 = 144? d2 = 144? d = 12 ? Length of diagonal = 12 cm, 24 cm
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 7 meters 21 meters 10.5 meters 5.25 meters 7 meters 21 meters 10.5 meters 5.25 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 120 sq m 125 sq m 115 sq m 111 sq m 120 sq m 125 sq m 115 sq m 111 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: 2.02% 4.04% 4% 2% 2.02% 4.04% 4% 2% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%
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