Area Problems The area of the sector of a circle, whose radius is 12 meters and whose angle at the centre is 42, is? 39.6 sq. meters 52.8 sq. meters 79.2 sq. meters 26.4 sq. meters 39.6 sq. meters 52.8 sq. meters 79.2 sq. meters 26.4 sq. meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the sector = [(22/7) x 12 x 12] x [42°/360°] m2 = 52.8 m2
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 15 meters None of these 4 meters 3 meters 15 meters None of these 4 meters 3 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems The length of a rectangular plot is twice of its width. If the length of a diagonal is 9?5 meters, the perimeter of the rectangular is? 54 m 27 m 81 m None of these 54 m 27 m 81 m None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = y meters,Then, length = 2y meters? Diagonal = ?y2 + (2y)2 = ?5y2 metersSo, ?5y2 = 9 ?5? y= 9Thus, breadth = 9 m and length = 18 m? Perimeter = 2 (18 + 9) m = 54m.
Area Problems The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by? 82% 42% 62% None of these 82% 42% 62% None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%
Area Problems In a rhombus, whose area is 144 sq.cmone of its diagonal is twice as long as the other, The lengths of its diagonals are? 24 cm, 48 cm 6 ?2 cm, 12?2 cm 12 cm, 24 cm 6 cm, 12 cm 24 cm, 48 cm 6 ?2 cm, 12?2 cm 12 cm, 24 cm 6 cm, 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus = (d1 x d2) / 2? (d x 2d ) / 2 = 144? d2 = 144? d = 12 ? Length of diagonal = 12 cm, 24 cm
Area Problems A park of 10 meters long and 8 meters broad. What is the length of the longest pole that can be placed in the park? 13.4 metres 10 metres 12.8 metres 18 metres 13.4 metres 10 metres 12.8 metres 18 metres ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of the longest pole = ? [(10)2 + (8)2] m = ? 164 m = 12.8 m
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