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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

9%
5%
6%
4%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?

20 m
50 m
40 m
30 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x meters. Then, Length = 115x / 100 meters Given that,  X × (115X / 100) = 460 => X = 20

Area Problems
The ratio of the area of two square, one having and double its diagonal than the other is?

3:2
3:1
2:1
4:1

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the diagonal of one square be (2d) cmThen, diagonal of another square = d cm? Area of first square = [ 1/2 x (2d)2] cm2Area of second square = (1/2 x d2) cm2? Ratio of area = (2d)2/ d2= 4/1 = 4: 1

Area Problems
An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

2%
2.02%
4%
4.04%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%

Area Problems
The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?

20 cm
30 cm
36 cm
24 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm

Area Problems
Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm.

20 cm
18 cm
14 cm
15 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm

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