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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

5%
9%
6%
4%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
A rectangular plot is half as long again as it broad. The area of the lawn is 2/3 hectares. The length of the plot is?

66.66 meters
33 meters
100 meters
(100/ ? 3 ) meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters. then, length = 3b/2 meters ? b x 3b/2 = 2/3 X 10000? b2 = (4 x 10000)/9? b = ( 2 X 100)/3 m ? Length = (3/2) x (2/3) x 100 m= 100 m

Area Problems
If the radius of a circle is increased by 6%, find the percentage increase in its area.

17%
12.36%
15%
8.39%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, a = 6 According to the formula,Percentage increase in area= 2a + [a2/100]%= 2 x 6 + [36/100]%= (12 + 0.36)%= 12.36%

Area Problems
The sides of a triangular board are 13 meters, 14 meters and 15 meters. The cost of paining it at the rate of Rs. 8.75 per m 2 is?

Rs. 735
Rs. 730.80
Rs. 688.80
Rs. 722.50

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

s = (13 + 14 + 15 ) / 2 = 21, s-a = 8 , s-b = 7, s-c= 6? Area to be painted = ? [s(s-a) (s-b) (s-c)]=? [21 x 8 x 7 x 6] m2= 84 m2? Cost of painting = Rs. (84 x 8.75) = Rs. 735

Area Problems
The length and perimeter of a rectangle are the ratio of 5 : 18 What well be the ratio of its length and breadth?

4 : 3
4 : 7
5 : 4
3 : 5

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,l/[2(l + b)] = 5/18? 10l + 10b = 18l = 10b? l/b = 10/8 = 5/4? l : b = 5 : 4Hence, ratio of length and breadth of a rectangle is 5 : 4

Area Problems
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

None of these
120
Data inadequate
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m

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