Area Problems If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals. 4% 5% 9% 6% 4% 5% 9% 6% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,Percentage increase in diagonals = 5%
Area Problems The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively. 14 cm and 6 cm 8 cm and 9 cm 10 cm and 8 cm 6 cm and 10 cm 14 cm and 6 cm 8 cm and 9 cm 10 cm and 8 cm 6 cm and 10 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the third side be x.According to the question,x + 20 = 26? x = 26 - 20 = 6 cm ? Each equal side = 20/2 = 10 cm
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 40 34 68 88 40 34 68 88 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
Area Problems The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and the breadth is increased by 5 cm, the area of the rectangle is increased by 75 cm 2 . Therefore , the length of the rectangle is? 20 cm 40 cm 30 cm 50 cm 20 cm 40 cm 30 cm 50 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b, length = 2b? Area of rectangle = 2b x b = 2b2As per question. ? (2b - 5 ) (b + 5 ) = 2b2 + 75? 5b = 75 + 25? 5b = 100? b = 100 / 5 = 20Hence, length of the rectangle =2b = 2 x 20 = 40 cm.
Area Problems Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm. 84 44 22 64 84 44 22 64 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let a = 13, b = 14 and c = 15. Then, s = 1 2 a + b + c =21 (s- a) = 8, (s - b) = 7 and (s - c) = 6. Area = s s - a s - b s - c = 21 × 8 × 7 × 6 = 84 sq.cm
Area Problems A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Rs. 258 Rs. 558 Rs. 458 Rs. 358 Rs. 258 Rs. 558 Rs. 458 Rs. 358 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = 2 l + b × h + l × b = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m Cost of plastering = 744 × 75 100 = R s . 558
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