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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

5%
6%
4%
9%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
A wheel makes 1000 revolutions in covering a distance of 88 km. the diameter of the wheel is?

14 meters
28 meters
24 meters
40 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Distance covered in one revolution = total distance travelled / total number of revolution. = ( 88 x 1000) / 1000 m = 88 mWe know that the distance covered in one revolution = circumference of the wheel.? ?d = 88? 22d / 7 = 88? d = 28 m

Area Problems
The area of a circular field is 13.86 hectares . The cost of fencing it at the rate of 20 paisa per meter is?

Rs. 264
Rs. 198
Rs. 324
Rs. 277.20

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 22/7 x r2 = 13.86 x 10000? r2 = (13.86 x 10000 x 7) / 22? r = 210 m ? Circumference = [2 x (22/7) x 210 ] m = 1320 m Cost of fencing = Rs. (1320 x 20)/100= Rs . 264

Area Problems
A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 6: 5 . The smaller side of the rectangle is?

60 cm
30 cm
132 cm
72 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Perimeter of rectangle = Circumference of circle = 2?r=2 x ( 22/7 ) x 42= 264 cm Now perimeter of rectangle = 2 x ( 6a + 5a )? 2 x (6a + 5a) = 264? a = 12Smaller side of rectangle = 5a = 60 cm

Area Problems
A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

Rs. 558
Rs. 458
Rs. 358
Rs. 258

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area to be plastered =  2 l + b × h + l × b   = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m   Cost of plastering =  744 × 75 100 = R s . 558

Area Problems
The ratio of the area of two square, one having and double its diagonal than the other is?

3:2
2:1
3:1
4:1

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the diagonal of one square be (2d) cmThen, diagonal of another square = d cm? Area of first square = [ 1/2 x (2d)2] cm2Area of second square = (1/2 x d2) cm2? Ratio of area = (2d)2/ d2= 4/1 = 4: 1

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