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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

4%
9%
6%
5%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
Area of a square is 1/2 hectare. The diagonal of the square is?

100 meter
50 meter
250 meter
50? 2 meter

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1/2 hectare = 10000 / 2 m2= 5000 m2Again Area = 1/2 x (Diagonal)2So 1/2 x (Diagonal)2 = 5000m2? Diagonal2= 10000 ? Diagonal = 100

Area Problems
If a regular hexagon is inscribed in a circle of radius, r then its perimeter?

6r
12r
3r
9r

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length of each side of hexagoan = radius of circle ? its perimeter = 6r

Area Problems
An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

2%
2.02%
4.04%
4%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%

Area Problems
The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm. Find the length of the smallest side of the triangle .

22.5 cm
24 cm
27 cm
18 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12Let length of the sides be 20k, 15k and 12k.Then, according to the question,20k + 15k + 12k = 94? 47k = 94? k = 94/47 = 2Smallest side = 12k = 12 x 2 = 24 cm

Area Problems
A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

10.08%
10%
28%
20%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let original length = x and original breadth = y. Decrease in area = xy - ❨ 80 x x 90 y ❩ 100 100 = ❨ xy - 18 xy ❩ 25 = 7 xy. 25 ∴ Decrease % = ❨ 7 xy x 1 x 100 ❩% = 28%

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