Area Problems If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals. 9% 4% 6% 5% 9% 4% 6% 5% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,Percentage increase in diagonals = 5%
Area Problems Square units 13 by 9 of an office area is 127 117 97 107 127 117 97 107 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
Area Problems The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is? 35 sq.cms 55 sq.cms 8. 75 sq.cms 17.5 sq.cms 35 sq.cms 55 sq.cms 8. 75 sq.cms 17.5 sq.cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.258 rs.158 rs.358 rs.58 rs.258 rs.158 rs.358 rs.58 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
Area Problems The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is? Rs. 810 Rs. 360 Rs. 1800 Rs. 900 Rs. 810 Rs. 360 Rs. 1800 Rs. 900 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900
Area Problems A wheel make 4000 revolution in moving a distance of 44 km. Find the radius of the wheel. 1.75 m 25 m 28 m 27 m 1.75 m 25 m 28 m 27 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in 1 revolution = (44 x 1000) / 4000 = 11 mAccording to the question, 2?r = 11 ? (44/7) x r = 11? r = (11 x 7) / 44 = 1.75 m
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