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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

6%
4%
5%
9%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is?

200
400
500
300

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square room = (10)2 = 100 sq m= 100 x (100)2 sq cm= 100 x 100 x 100 sq cmNow, area of tiles = (50)2 = 50 x 50 sq cm? Number of tiles needed = (Area of square room) / (Area of tile)= (100 x 100 x 100) / (50 x 50) = 400Hence, 400 tiles will be needed.

Area Problems
The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively.

6 cm and 10 cm
10 cm and 8 cm
8 cm and 9 cm
14 cm and 6 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the third side be x.According to the question,x + 20 = 26? x = 26 - 20 = 6 cm ? Each equal side = 20/2 = 10 cm

Area Problems
A circular disc of area 0.49 ? square meters, rolls down a length of 1.76 km. The number of revolutions it makes is?

4000
600
400
300

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = ?r2 = 0.49? ? r = 0.7 mNumber of revolutions = total distance / circumference = (1.76 x 1000) / (2 x 22/7 x 0.7) = 400

Area Problems
Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm.

15 cm
18 cm
20 cm
14 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm

Area Problems
A rectangle has 15 cm as its length and 150 cm 2 as its area .Its area is increased to 1 1 / 3 times the original area by increasing only its length . Its new perimeter is?

60 cm
50 cm
80 cm
70 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Breadth of the rectangle = (150/15) cm= 10 cmNew area = (4/3 x 150) cm2= 200 cm2New length = 200/10 cm=20 cmNew perimeters = 2(20 + 10) cm= 60 cm

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