Let the longer side = l, shorter side = b and diagonal = dThen, area of rectangular carpet = l x b = 60 ....(1) And from question d + l = 5b? d = 5b - l ...(2)? d2 = 25b2 + l2 - 10 x lb? l2+ b2 = 25b2 + l2 - 10 x lb? l2+b2 = 25b2 + l2 - 10 x 60? 24b2 = 600? b = ?25 = 5 m? l = 60 / b = 60 / 5 = 12 m
In a triangleSum of two sides is always greater than 3rd side i.e., x < 25 + 15 = 40 .....(i)Difference of two sides is always less than 3rd side i.e., 25 - 15 = 10 < x ...(ii) From Eqs. (i) and (ii) , we get 10 < x < 40
Area of square = 64 sq cm (Side)2 = 64 ? Side = ?64 = 8 cmAccording to the question,? 2?r = 4 x 8 ? r = (4 x 8)/2?? r = 16/?? Area of the circle = ? x (16/?) x (16/?) sq cm = 256/? sq cm.
Given that, l = 2b [Here l = length and b = breadth]Decrease in length = Half of the 10 cm = 10/2 = 5 cmIncrease in breadth = Half of the 10 cm = 10/2 = 5 cm Increase in the area = (70 + 5) = 75 sq cm According to the question, (l - 5) (b + 5) = lb + 75 ? (2b - 5) (b + 5) = 2b2 + 75 [since l = 2b]? 5b - 25 = 75 ? 5b = 100? b = 100/ 5 = 20? l = 2b = 2 x 20 = 40 cm
EXAMIANS