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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

5%
6%
9%
4%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
The area of a trapezium is 384 sq.cm. If its parallel sides in ratio 3 : 5 and the perpendicular distance between them be 12 cm. The smaller of parallel sides is?

24 cm
32 cm
16 cm
40 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the parallel sides be 3a and 5a.So Area of trapezium = 1/2 x sum of parallel side x perpendicular distance between them.? 1/2 (3a +5a) x 12 = 384? 8a = 64? a =8? Smaller side = 3x = 3 x 8 = 24 cm.

Area Problems
The ratio of the area of the circumcircle and the incircle of a square is

?2 : 1
1 : ?2
2 : 1
1 : 2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1

Area Problems
The perimeter of two square is 12 cm and 24 cm. The area of the bigger square is how many times that of the smaller?

3 times
5 times
2 times
4 times

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)2= (24/12)2= 4

Area Problems
In a circle of radius 21 cm an arc subtends an angle of 72° at the centre. The length of the arc is?

21.6 cm
13.2 cm
19.8 cm
26.4 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Arc length = 2?r (?° / 360°) = 2 x (22/7) x 21 x (72° / 360°) cm= 26.4 cm

Area Problems
The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is?

9 sq. meters .
12 sq. meters .
18 sq. meters .
6 sq. meters .

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2

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