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Area Problems

Area Problems
If the sides of a rectangle are increased by 5%, find the percentage increase in its diagonals.

9%
4%
6%
5%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the formula,Percentage increase in diagonals = 5%

Area Problems
Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

1.567
1.967
1.867
1.767

ANSWER DOWNLOAD EXAMIANS APP

Area Problems
The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?

24 cm
30 cm
36 cm
20 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm

Area Problems
The altitude of an equilateral triangle of side 2 ? 3 cm is?

1/2 cm
? 3/4
? 3/2 cm
3 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.

Area Problems
Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

76m
16m
14m
56m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.
Let the length of the rope be r mts  then,
r2 = 9856
r2 = (9856 × 7) / 22 = 3136
r = 56 m

Area Problems
A wheel make 4000 revolution in moving a distance of 44 km. Find the radius of the wheel.

1.75 m
28 m
25 m
27 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Distance covered in 1 revolution = (44 x 1000) / 4000 = 11 mAccording to the question, 2?r = 11 ? (44/7) x r = 11? r = (11 x 7) / 44 = 1.75 m

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