JAVA Exceptions
What happen in case of multiple catch blocks?

Either super or subclass can be caught first.
The superclass exception cannot caught first.
The superclass exception must be caught first.
None of these

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"exception" is printed.
"one" is printed.
"null pointer exception" is printed.
None of these
Compilation fails saying NullPointerException has already been caught.

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JAVA Exceptions
Given the following piece of code:class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}Which of the following statements is correct?1. This code will compile without any problems.2. This code will compile if in method paySalaries() we return a boolean in stead of void.3. This code will compile if we add a try-catch block in paySalaries().4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries().

3 and 4
1 and 4
2 and 4
1 and 2
2 and 3

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