JAVA Exceptions
What happen in case of multiple catch blocks?

The superclass exception cannot caught first.
The superclass exception must be caught first.
Either super or subclass can be caught first.
None of these

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

None of these
"exception" is printed.
"one" is printed.
Compilation fails saying NullPointerException has already been caught.
"null pointer exception" is printed.

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JAVA Exceptions
What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }}

Compilation fails-Exception NullPointerException is not compatible with throws clause in
Name-B
Value-A
None of these
Compilation succeed but no output
printName()

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