JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"null pointer exception" is printed.
"exception" is printed.
None of these
Compilation fails saying NullPointerException has already been caught.
"one" is printed.

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JAVA Exceptions
Given the code. What is the result when this program is executed?public class Test{ static int x[]; static{ x[0] = 1; } public static void main(String args[]){ }}

None of these
StackOverflowException is thrown
IllegalStateException is thrown
ExceptionInInitializerError is thrown
ArrayIndexOutOfBoundsException is thrown

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

This code will not compile, because in Java there are no pointers.
There is a NullPointerException. There is an Exception.
There is a NullPointerException. Everything went fine.
There is a NullPointerException.

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