JAVA Exceptions
What will be the result if NullPointerException occurs at line 2?1. try{2. //some code goes here3. }4. catch(NullPointerException ne){5. System.out.print("1 ");6. }7. catch(RuntimeException re){8. System.out.print("2 ");9. }10. finally{11. System.out.print("3");12. }

1 3
2 3
1 2 3
1
3

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

There is a NullPointerException. Everything went fine.
This code will not compile, because in Java there are no pointers.
There is a NullPointerException.
There is a NullPointerException. There is an Exception.

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

Compilation fails saying NullPointerException has already been caught.
"one" is printed.
"null pointer exception" is printed.
None of these
"exception" is printed.

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