JAVA Exceptions
What will be the result if NullPointerException occurs at line 2?1. try{2. //some code goes here3. }4. catch(NullPointerException ne){5. System.out.print("1 ");6. }7. catch(RuntimeException re){8. System.out.print("2 ");9. }10. finally{11. System.out.print("3");12. }

3
1
2 3
1 2 3
1 3

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

None of these
"exception" is printed.
Compilation fails saying NullPointerException has already been caught.
"one" is printed.
"null pointer exception" is printed.

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