JAVA Exceptions
What is the output of the following program code?public class Test{ public static void main(String args[]){ try{ int i; return; } catch(Exception e){ System.out.print("inCatchBlock"); } finally{ System.out.println("inFinallyBlock"); } }}

inCatchBlock
inCatchBlock inFinallyBlock
The program will return without printing anything
inFinallyBlock

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

There is a NullPointerException. Everything went fine.
There is a NullPointerException.
There is a NullPointerException. There is an Exception.
This code will not compile, because in Java there are no pointers.

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