JAVA Exceptions
What is the output of the following program code?public class Test{ public static void main(String args[]){ try{ int i; return; } catch(Exception e){ System.out.print("inCatchBlock"); } finally{ System.out.println("inFinallyBlock"); } }}

inCatchBlock inFinallyBlock
inFinallyBlock
inCatchBlock
The program will return without printing anything

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JAVA Exceptions
What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }}

Compilation fails-Exception NullPointerException is not compatible with throws clause in
printName()
Compilation succeed but no output
Value-A
None of these
Name-B

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

Compile with error
Prints out: Exception Finally
Prints out: Finally
None of these
Prints out: Exception

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

There is a NullPointerException. Everything went fine.
There is a NullPointerException. There is an Exception.
This code will not compile, because in Java there are no pointers.
There is a NullPointerException.

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

Compilation fails saying NullPointerException has already been caught.
"one" is printed.
None of these
"null pointer exception" is printed.
"exception" is printed.

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