JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

This code will not compile, because in Java there are no pointers.
There is a NullPointerException. There is an Exception.
There is a NullPointerException. Everything went fine.
There is a NullPointerException.

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JAVA Exceptions
What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }}

"doCdoBdoA" is printed
"doBdoAerror" is printed
nothing is printed
"doAdoBdoC" is printed
"error" is printed

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

Prints out: Exception
Compile with error
None of these
Prints out: Exception Finally
Prints out: Finally

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