JAVA Exceptions Given the code. What is the result when this program is executed?public class Test{ static int x[]; static{ x[0] = 1; } public static void main(String args[]){ }} None of these ArrayIndexOutOfBoundsException is thrown IllegalStateException is thrown ExceptionInInitializerError is thrown StackOverflowException is thrown None of these ArrayIndexOutOfBoundsException is thrown IllegalStateException is thrown ExceptionInInitializerError is thrown StackOverflowException is thrown ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Exception generated in try block is caught in ........... block. throw finally throws catch throw finally throws catch ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }} Compilation fails-Exception NullPointerException is not compatible with throws clause in Compilation succeed but no output None of these Value-A Name-B printName() Compilation fails-Exception NullPointerException is not compatible with throws clause in Compilation succeed but no output None of these Value-A Name-B printName() ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Which keyword is used to specify the exception thrown by method? finally catch throw throws finally catch throw throws ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }} "null pointer exception" is printed. "one" is printed. "exception" is printed. None of these Compilation fails saying NullPointerException has already been caught. "null pointer exception" is printed. "one" is printed. "exception" is printed. None of these Compilation fails saying NullPointerException has already been caught. ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }} Compile with error None of these Prints out: Exception Prints out: Finally Prints out: Exception Finally Compile with error None of these Prints out: Exception Prints out: Finally Prints out: Exception Finally ANSWER DOWNLOAD EXAMIANS APP
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